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Ζ_ΣΥΝΑΡΤΗΣΕΙΣ_ΑΝΤΙΣΤΡΟΦΗ

Authored by giannis xantzis

Mathematics

10th Grade

Used 2+ times

Ζ_ΣΥΝΑΡΤΗΣΕΙΣ_ΑΝΤΙΣΤΡΟΦΗ
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25 questions

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1.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Αν f(x) = 2x + 5 , τότε f(2) = . . .

2

5

9

12

Answer explanation

f(2) = 2 . 2 + 5

f(2) = 4 + 5

f(2) = 9

2.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Αν f(x) = 2x + 5 , τότε f(-2) = . . .

-9

1

5

0

Answer explanation

f(-2) = 2 . (-2) + 5

f(-2) = - 4 + 5

f(-2) = 1

3.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Δίνεται η συνάρτηση f(x) = 2x + 5 .

Αν f(κ) = - 15, τότε κ = . . .

-5

10

5

-10

Answer explanation

f(κ) = -15 δηλαδή

2κ + 5 = - 15 και

χωρίζω γνωστούς από αγνώστους

2κ = - 15 - 5

2κ = - 20

κ = - 10

4.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Δίνεται η συνάρτηση f(x) = 2x + 5 .

Αν f(κ) = - 15, τότε κ = . . .

-5

10

5

-10

Answer explanation

f(κ) = -15 δηλαδή

2κ + 5 = - 15 και

χωρίζω γνωστούς από αγνώστους

2κ = - 15 - 5

2κ = - 20

κ = - 10

5.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Δίνονται δύο συναρτήσεις f(x) = 2x - 5 και g(x) = 3x + m.

Aν g(1) = f(4) ,

τότε m = . . .

m = 0

m = 1

m = -1

m = 2

6.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Δίνεται συνάρτηση τέτοια, ώστε

f(2x + 5) = 6x - 8.

Το f(5) = . . .

f(5) = 22

f(5) = - 8

f(5) = 0

Answer explanation

Για να βρούμε το f(0) βάζουμε

όπου x = 0.

Οπότε f(2.0+ 5) = 6.0 - 8

f(5) = 0 - 8

f(5) = - 8

7.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Δίνεται συνάρτηση τέτοια, ώστε

f(2x + 5) = 6x - 8.

Το f(9) = . . .

f(9) = 46

f(9) = - 8

f(9) = 4

Answer explanation

Για να βρούμε το f(9) βάζουμε

όπου x = 2.

Οπότε f(2.2+ 5) = 6.2 - 8

f(9) = 12 - 8

f(9) = 4

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