How do you solve? x + 5 = 10 x+5=10 x + 5 = 1 0

− 5 o n b o t h s i d e s -5\ on\ both\ sides − 5 o n b o t h s i d e s

+ 5 o n b o t h s i d e s +5\ on\ both\ sides + 5 o n b o t h s i d e s

÷ 5 o n b o t h s i d e s \div5\ on\ both\ sides ÷ 5 o n b o t h s i d e s

× 5 o n b o t h s i d e s \times5\ on\ both\ sides × 5 o n b o t h s i d e s

How do you solve? x − 3 = 4 x-3=4 x − 3 = 4

+ 3 o n b o t h s i d e s +3\ on\ both\ sides + 3 o n b o t h s i d e s

− 3 o n b o t h s i d e s -3\ on\ both\ sides − 3 o n b o t h s i d e s

× 3 o n b o t h s i d e s \times3\ on\ both\ sides × 3 o n b o t h s i d e s

÷ 3 o n b o t h s i d e s \div3\ on\ both\ sides ÷ 3 o n b o t h s i d e s

How do you solve? 3 x ≡ 12 3x\equiv12 3 x ≡ 1 2

÷ 3 o n b o t h s i d e s \div3\ on\ both\ sides ÷ 3 o n b o t h s i d e s

+ 3 o n b o t h s i d e s +3\ on\ both\ sides + 3 o n b o t h s i d e s

− 3 o n b o t h s i d e s -3\ on\ both\ sides − 3 o n b o t h s i d e s

x 13 = 3 \frac{x}{13}=3 1 3 x = 3

x = 3 13 x=\frac{3}{13} x = 1 3 3

13 + x = 15 13+x=15 1 3 + x = 1 5

x = 1 1 3 x=1\frac{1}{3} x = 1 3 1

x 3 = 4 \frac{x}{3}=4 3 x = 4

x = 1 1 3 x=1\frac{1}{3} x = 1 3 1

x − 20 = − 10 x-20=-10 x − 2 0 = − 1 0

x = − 200 x=-200 x = − 2 0 0

x = − 1 2 x=-\frac{1}{2} x = − 2 1

v + 19 = − 1 v+19=-1 v + 1 9 = − 1

v = − 1 19 v=-\frac{1}{19} v = − 1 9 1

m − 9 = − 21 m-9=-21 m − 9 = − 2 1

m = − 189 m=-189 m = − 1 8 9

m = − 7 3 m=-\frac{7}{3} m = − 3 7

b − 13 = 4 b-13=4 b − 1 3 = 4

b = 4 13 b=\frac{4}{13} b = 1 3 4

n − 20 = − 32 n-20=-32 n − 2 0 = − 3 2

n = − 1 3 5 n=-1\frac{3}{5} n = − 1 5 3

n = − 640 n=-640 n = − 6 4 0

a + 3 = − 1 a+3=-1 a + 3 = − 1

a = − 1 3 a=-\frac{1}{3} a = − 3 1

x 9 = 11 \frac{x}{9}=11 9 x = 1 1

x = 1 2 9 x=1\frac{2}{9} x = 1 9 2

One Step Equations Review

6th - 8th Grade

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Practice Problem

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Hard

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CCSS

6.EE.B.7, HSA.CED.A.3, HSA.REI.A.1

Standards-aligned

Ben DeVito

FREE Resource

68 questions

Show all answers

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

What is the inverse (opposite) of addition?

Tags

CCSS.HSA.REI.A.1

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

What is the inverse (opposite) of subtraction?

Tags

CCSS.HSA.REI.A.1

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

What is the inverse (opposite) of multiplication?

Tags

CCSS.HSA.REI.A.1

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

What is the inverse (opposite) of division?

Tags

CCSS.HSA.REI.A.1

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

How do you solve?
$x+5=10$

$-5\ on\ both\ sides$

$+5\ on\ both\ sides$

$\div5\ on\ both\ sides$

$\times5\ on\ both\ sides$

Tags

CCSS.6.EE.B.7

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

How do you solve?
$x-3=4$

$-3\ on\ both\ sides$

$+3\ on\ both\ sides$

$\times3\ on\ both\ sides$

$\div3\ on\ both\ sides$

Tags

CCSS.6.EE.B.7

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

How do you solve?
$3x\equiv12$

$+3\ on\ both\ sides$

$-3\ on\ both\ sides$

$\div3\ on\ both\ sides$

Tags

CCSS.6.EE.A.2

CCSS.6.EE.B.5

CCSS.6.EE.B.6

CCSS.6.EE.B.7

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Solve:
$x+5=10$

$x=5$

$x=15$

$x=50$

Tags

CCSS.6.EE.B.7

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Solve:
$x-3=12$

$x=9$

$x=15$

$x=4$

Tags

CCSS.6.EE.B.7

10.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Solve:
$3x=12$

$x=9$

$x=15$

$x=4$

Tags

CCSS.6.EE.B.7

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One Step Equations Review

68 questions

What is the inverse (opposite) of addition?

What is the inverse (opposite) of subtraction?

What is the inverse (opposite) of multiplication?

What is the inverse (opposite) of division?

How do you solve? x+5=10x+5=10x+5=10

How do you solve? x−3=4x-3=4x−3=4

How do you solve? 3x≡123x\equiv123x≡12

Solve: x+5=10x+5=10x+5=10

Solve: x−3=12x-3=12x−3=12

Solve: 3x=123x=123x=12

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Discover more resources for Mathematics

How do you solve?
$x+5=10$

How do you solve?
$x-3=4$

How do you solve?
$3x\equiv12$

Solve:
$x+5=10$

Solve:
$x-3=12$

Solve:
$3x=12$