Impulse, Momentum, and Projectile Motion

Impulse, Momentum, and Projectile Motion

12th Grade

16 Qs

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Impulse, Momentum, and Projectile Motion

Impulse, Momentum, and Projectile Motion

Assessment

Quiz

Physical Ed

12th Grade

Hard

Created by

ormond heather

FREE Resource

16 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Imagine Henry, Daniel, and Charlotte are on the soccer field, and Henry just kicked the ball with all his might! Can you define impulse and explain how it connects to momentum in the exciting context of Henry's powerful kick?

Impulse is the total momentum of an object.

Momentum is defined as the force applied over time.

Impulse is the change in momentum, defined as J = F * Δt, and relates to momentum through the impulse-momentum theorem.

Impulse is the product of mass and velocity.

Answer explanation

The correct choice defines impulse as the change in momentum (J = F * Δt) and connects it to momentum through the impulse-momentum theorem, highlighting their direct relationship.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Grace is having a blast playing with a 5 kg ball that she throws at a speedy 10 m/s. Can you calculate the impulse experienced by the ball when it comes to a complete stop? Let's see if you can figure it out!

0 kg m/s

-50 kg m/s

-25 kg m/s

50 kg m/s

Answer explanation

Impulse is the change in momentum. The initial momentum is 5 kg * 10 m/s = 50 kg m/s. Coming to a stop means final momentum is 0 kg m/s. Thus, impulse = 0 - 50 = -50 kg m/s, which is the correct answer.

3.

MATCH QUESTION

30 sec • 1 pt

Match the following impulses with their corresponding force and time.

Force of 10 N for 3 seconds

50 Ns

Force of 20 N for 3 seconds

80 Ns

Force of 40 N for 2 seconds

60 Ns

Force of 25 N for 2 seconds

30 Ns

Answer explanation

Impulse is calculated as the product of force and time. Here, impulse = force × time = 20 N × 3 s = 60 Ns. Therefore, the correct answer is 60 Ns.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Imagine Elijah and his friends David and Evelyn are on the soccer field, and Elijah kicks the ball with all his might! Can you explain how impulse can change the momentum of the ball?

Impulse is the same as momentum and does not change it.

Impulse changes the momentum of the ball by applying a force over time, resulting in a change in momentum equal to the impulse.

Impulse has no effect on the motion of the ball.

Momentum can only be changed by increasing the ball's mass.

Answer explanation

Impulse changes momentum by applying a force over a period of time. This results in a change in momentum that is equal to the impulse applied, making the correct choice the one that explains this relationship.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Hey there! Rohan is gearing up for an exciting physics experiment! He’s launching a projectile at a thrilling angle of 30 degrees with an initial velocity of 20 m/s. Can you help him figure out the horizontal and vertical components of the velocity?

Horizontal component: 17.32 m/s, Vertical component: 10 m/s

Horizontal component: 10 m/s, Vertical component: 17.32 m/s

Horizontal component: 20 m/s, Vertical component: 0 m/s

Horizontal component: 15 m/s, Vertical component: 12 m/s

Answer explanation

To find the components of velocity, use the formulas: Vx = V * cos(θ) and Vy = V * sin(θ). For θ = 30° and V = 20 m/s, Vx = 20 * cos(30°) = 17.32 m/s and Vy = 20 * sin(30°) = 10 m/s. Thus, the correct choice is: Horizontal component: 17.32 m/s, Vertical component: 10 m/s.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Emma is having a blast at the park, launching a projectile with a speed of 25 m/s at a thrilling angle of 45 degrees! Can you help her calculate the time of flight for her exciting launch?

5.00 seconds

3.57 seconds

2.50 seconds

4.20 seconds

Answer explanation

To find the time of flight, use the formula: T = (2 * v * sin(θ)) / g. Here, v = 25 m/s, θ = 45°, and g = 9.81 m/s². This gives T = (2 * 25 * sin(45°)) / 9.81 ≈ 3.57 seconds, which is the correct answer.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Hey there, physics enthusiasts! Arjun is gearing up to launch a projectile at a speed of 15 m/s, angled perfectly at 60 degrees. Can you help him figure out the maximum height that this exciting launch will reach?

8.60 m

12.30 m

10.50 m

5.00 m

Answer explanation

To find the maximum height, use the formula h = (v^2 * sin^2(θ)) / (2 * g). Here, v = 15 m/s, θ = 60°, and g = 9.81 m/s². This gives h = (15^2 * (√3/2)^2) / (2 * 9.81) = 8.60 m.

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