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10.24 Functions on the Unit Circle

Authored by Kayla Hagerty Simmons

Mathematics

9th - 12th Grade

CCSS covered

Used 1+ times

10.24 Functions on the Unit Circle
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15 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

0

undefined

1

-1

Answer explanation

The secant function, \sec(x), is defined as \frac{1}{\cos(x)}. At \frac{3\pi}{2}, \cos\left(\frac{3\pi}{2}\right) = 0, making \sec\left(\frac{3\pi}{2}\right) undefined.

Tags

CCSS.HSF.TF.A.2

2.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Answer explanation

To find \( \sin\left(\frac{7\pi}{6}\right) \), note that \( \frac{7\pi}{6} \) is in the third quadrant where sine is negative. The reference angle is \( \frac{\pi}{6} \), giving \( \sin\left(\frac{7\pi}{6}\right) = -\frac{1}{2} \).

Tags

CCSS.HSF.TF.A.2

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

undefined

0

1

-1

Answer explanation

The tangent function, \( \tan(x) \), is periodic with a period of \( \pi \). Thus, \( \tan(-3\pi) = \tan(0) = 0 \). Therefore, the correct answer is 0.

Tags

CCSS.HSF.TF.A.2

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Answer explanation

The angle \( \frac{3\pi}{4} \) is in the second quadrant of the unit circle. The coordinates are given by \( \left( \cos \frac{3\pi}{4}, \sin \frac{3\pi}{4} \right) = \left( -\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2} \right) \).

Tags

CCSS.HSF.TF.A.2

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

I

II

III

IV

Answer explanation

The angle -\frac{2\pi}{3} radians is equivalent to 240 degrees, which lies in the third quadrant where both sine and cosine values are negative. Therefore, the correct answer is III.

Tags

CCSS.HSF.TF.A.2

6.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

What is the radius of a unit circle?

1

2

Answer explanation

A unit circle is defined as a circle with a radius of 1. Therefore, the correct answer is 1, as it represents the radius of a unit circle.

Tags

CCSS.HSF.TF.A.2

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Answer explanation

To find \( \csc\left(\frac{3\pi}{4}\right) \), we first find \( \sin\left(\frac{3\pi}{4}\right) = \frac{\sqrt{2}}{2} \). The cosecant is the reciprocal, so \( \csc\left(\frac{3\pi}{4}\right) = \frac{1}{\sin\left(\frac{3\pi}{4}\right)} = \sqrt{2} \).

Tags

CCSS.HSF.TF.A.2

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