October 25th Friction Intro
Authored by Brent Thomas
Physics
11th Grade
18 Questions
NGSS covered
Used 7+ times
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1.
OPEN ENDED QUESTION
3 mins • 1 pt
Describe the difference between static and kinetic friction.
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Answer explanation
Static friction is the friction between two surfaces in contact that are not moving. Dynamic friction is the friction between two surfaces in contact that are moving.
2.
OPEN ENDED QUESTION
3 mins • 1 pt
What information does the coefficient of friction tell us?
What information does the coefficient of friction tell us?
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Answer explanation
Coefficient of friction is the amount of resistance that a surface exerts on an object moving over it.
Tags
NGSS.HS-PS2-1
3.
OPEN ENDED QUESTION
3 mins • 1 pt
The table shows the coefficient of friction for three objects of identical mass. Which object will experience the largest magnitude of friction? Explain how you know.
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Answer explanation
Object 2 will experience the largest magnitude of friction because it has the highest coefficient of friction.
4.
OPEN ENDED QUESTION
3 mins • 1 pt
The free body diagram represents athlete who is jogging prior to experiencing a concussion. Is the athlete in equilibrium? Explain how you know.
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Answer explanation
Yes, the net force is 0 N.
Tags
NGSS.HS-PS2-1
5.
OPEN ENDED QUESTION
3 mins • 1 pt
What is the relationship between coefficient of friction and the amount of resistance a surface has?
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Answer explanation
There is a directly proportional relationship between the coefficient of friction and the amount of resistance the surface has. The higher the coefficient of friction, the more resistance. This resistance is the force of friction.
6.
OPEN ENDED QUESTION
3 mins • 1 pt
The box has a mass of 25 kg and is experiencing a net force of 125 N to the right. Calculate the force of friction.
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Answer explanation
Sum the forces in the x-direction, right is positive, 450N-F (left) = 125N
F(left) = 325N
Tags
NGSS.HS-PS2-1
7.
OPEN ENDED QUESTION
3 mins • 1 pt
The box has a mass of 30 kg and is accelerating at a rate of -0.5 m/s2. Calculate the force of friction.
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Answer explanation
Sum of the forces =ma,
175N - Ff = 30 kg (-0.5 m/s2)
Ff= 190N
Tags
NGSS.HS-PS2-1
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