CYU 2.6 Money Word Problems

The number of five-dollar bills is triple g. What is the algebraic expression for the number of five-dollar bills?

• 3g

• g

• g/3

• g + 3

Tags

CCSS.HSA-SSE.A.1A

The number of dimes is 6 less than x. What is the algebraic expression for the total monetary value of the dimes?

• x - 6

• 6 - x

• 0.10(6 - x)

• 0.10(x - 6)

Tags

CCSS.HSA-SSE.A.1A

John has four more nickels than dimes in his pocket, for a total of $1.25. How many dimes and how many nickels does John have?

• 7 dimes and 11 nickels

• 11 dimes and 7 nickels

• 5 dimes and 9 nickels

• 6 dimes and 10 nickels

Tags

CCSS.8.EE.C.8C

Harley has 3 less quarters than nickels in his pocket, for a total of $3.75. How many quarters and how many nickels does John have?

• 12 quarters and 15 nickels

• 15 quarters and 12 nickels

• 15 quarters and 18 nickels

• 18 quarters and 15 nickels

Tags

CCSS.8.EE.C.8C

Liam has a collection of dimes and quarters that together total $4.50. He has twice as many dimes as quarters. Which equation can be used to find the number of each type of coin Liam has?

• 2x+x=4.50

• 0.10(x)+0.25(2x)=4.50

• 0.25(x)+0.10(2x)=4.50

• 0.25(2x)=4.50

Tags

CCSS.HSA.CED.A.3

Emma has a collection of nickels and dimes that together total $3.00. She has three times as many nickels as dimes. Which equation can be used to find the number of each type of coin Emma has?

• 3x+x=3.00

• 0.05(x)+0.10(3x)=3.00

• 0.10(x)+0.05(3x)=3.00

• 0.10(3x)=3.00

Tags

CCSS.6.EE.B.6

CCSS.6.EE.B.7

CCSS.6.EE.A.2

Maria has a collection of nickels and pennies worth a total of $0.44. If she has 2 more than twice as many pennies as nickels, which equation can be used to find out how many of each coin Maria has?

• 0.05n + 0.01 = 0.44
• 0.10p + 0.02p = 0.44

• 0.01(2x+2) + 0.05x = 0.44

• 2x + 2 + x = 0.44

Tags

CCSS.8.EE.C.7B

Sophia has a collection of quarters and nickels worth a total of $2.75. If she has five more quarters than nickels, which equation can be used to find out how many of each coin Sophia has?

• 0.25(x+5) + 0.05x = 2.75

• 0.05(x+5) + 0.25x = 2.75

• x + (x+5) = 2.75

• 5x + 25(x+5) = 2.75

Olivia has a collection of dimes and nickels that together total $1.80. She has twice as many nickels as dimes. Which equation can be used to find the number of each type of coin Olivia has?

• 0.10(x) + 0.05(2x) = 1.80

• 0.05(x) + 0.10(2x) = 1.80

• (2x) + (x) = 1.80

• 5(2x) + 10(x) = 1.80

Tags

CCSS.HSA.CED.A.3

Lucas has a collection of nickels and quarters worth a total of $3.50. He has 7 more than twice as many nickels as quarters. Which equation can be used to find the number of each type of coin Lucas has?

• 0.05(2x+7) + 0.25(x) = 3.50

• 0.25(3x) + 0.05(2x-7) = 3.50

• 0.05(x) + 0.25(2x+7) = 3.50

• x + 2x + 7 = 3.50

Tags

CCSS.8.EE.C.7B