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3rosecunda

Authored by Alexis Bolivar

Mathematics

1st - 5th Grade

Used 1+ times

3rosecunda
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10 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Halla "x"

7

8

9

10,5

12,5

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

 Halla: “X”

 21\sqrt{21}  

 19\sqrt{19}  

 17\sqrt{17}  

5

4

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Teorema que relaciona los lados de un triángulo y la altura relativa a uno de ellos.

Primer Teorema de Euclides

Teorema de Herón

Teorema de la median

Segundo Teorema de Euclides

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

De la figura, sabiendo que

 mcm_c  es mediana, se cumple que ...

 c2+a2=2mc2+b22c^2+a^2=2m_c^2+\frac{b^2}{2}  

 a2+b2=2mc2+c22a^2+b^2=2m_c^2+\frac{c^2}{2}  

 a2+mc2=2b2+c22a^2+m_c^2=2b^2+\frac{c^2}{2}  

 a2+b2=mc22+2c2a^2+b^2=\frac{m_c^2}{2}+2c^2  

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

En el triángulo ABC se cumple el teorema de Herón, sabiendo que  p p\   : semi-perímetro...

 h=2bp(p−3a)(p−3b)(p−3c)h=\frac{2}{b}\sqrt{p\left(p-3a\right)\left(p-3b\right)\left(p-3c\right)}  

 h=2bp(p−2a)(p−2b)(p−2c)h=\frac{2}{b}\sqrt{p\left(p-2a\right)\left(p-2b\right)\left(p-2c\right)}  

 h=2bp(p−a)(p−b)(p−c)h=\frac{2}{b}\sqrt{p\left(p-a\right)\left(p-b\right)\left(p-c\right)}  

 h=2b2p(2p−3a)(2p−3b)(2p−3c)h=\frac{2}{b}\sqrt{2p\left(2p-3a\right)\left(2p-3b\right)\left(2p-3c\right)}  

 h=2b2p(2p−a)(2p−b)(2p−c)h=\frac{2}{b}\sqrt{2p\left(2p-a\right)\left(2p-b\right)\left(2p-c\right)}  

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Siendo  xcx_c   bisectriz interior del triángulo ABC, entonces se cumple el teorema de la bisectriz el cual es...

 xc2=ab−mnx_c^2=ab-mn  

 xc2=mn−abx_c^2=mn-ab  

 xc=a2b−mnx_c^{ }=a^2b-mn  

 xc=a2b2−mnx_c^{ }=a^2b^2-mn  

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

En la figura también se cumple que...

hb=achb=ac

ha=cbha=cb

h2b=ach^2b=ac

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