Understanding Reaction Mechanisms

Understanding Reaction Mechanisms

Assessment

Interactive Video

Chemistry, Science

11th Grade - University

Hard

Created by

Olivia Brooks

FREE Resource

The video explores the impact of changing a nucleophile from methoxide to a bulkier tert-butyl group on reaction types. It explains how this change affects the reaction mechanism, shifting from Sn2 to E2 due to the bulky nucleophile's inability to act effectively. The video also covers the role of the solvent, dimethylformamide, and provides a detailed explanation of the E2 reaction mechanism with the new base.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main focus of the video?

Exploring a new solvent

Understanding a different reaction type

Learning about methoxide

Discussing reaction temperatures

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the key difference between methoxide and the new nucleophile?

The new nucleophile is smaller

The new nucleophile has a different charge

The new nucleophile is less reactive

The new nucleophile is bonded to a carbon with three methyl groups

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What type of solvent is dimethylformamide?

Protic

Aprotic

Non-polar

Polar

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is methoxide considered a strong nucleophile?

It is a weak base

It can easily react with substrates

It is bonded to a carbon

It is a large molecule

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How does the bulky nature of the new nucleophile affect its reactivity?

It becomes a weaker nucleophile

It reacts faster with substrates

It becomes a stronger nucleophile

It is unaffected by its size

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What reaction pathway does the bulky nucleophile favor?

E2

Sn2

Sn1

E1

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to the hydrogen's electron in the reaction mechanism?

It remains with the hydrogen

It goes to the alpha carbon

It is lost to the environment

It is transferred to the solvent

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