Front

What is the Perpendicular Bisector Theorem?

Back

The Perpendicular Bisector Theorem states that if a point is on the perpendicular bisector of a segment, then it is equidistant from the endpoints of the segment.

Front

How do you find the length of a segment using the Perpendicular Bisector Theorem?

Back

To find the length of a segment using the Perpendicular Bisector Theorem, identify the midpoint of the segment and use the distances from the midpoint to the endpoints.

Front

What is the relationship between the lengths of segments created by a perpendicular bisector?

Back

The lengths of the segments created by a perpendicular bisector are equal to each other.

Front

If JM = 12, what can you infer about the segments created by the perpendicular bisector?

Back

If JM = 12, then the segments created by the perpendicular bisector are each 6 units long, as they are equal.

Front

What is the significance of the midpoint in the Perpendicular Bisector Theorem?

Back

The midpoint is significant because it is the point that divides the segment into two equal parts and is where the perpendicular bisector intersects.

Front

How can you determine if a point lies on the perpendicular bisector of a segment?

Back

A point lies on the perpendicular bisector of a segment if it is equidistant from the endpoints of the segment.

Front

What is the measure of Segment TP if it is bisected and one part is 7?

Back

If Segment TP is bisected and one part is 7, then the total length of Segment TP is 14.

Front

If the measure of segment LP is 15, what does this imply about the segments created by its perpendicular bisector?

Back

If the measure of segment LP is 15, then each segment created by its perpendicular bisector measures 7.5.

Front

What is the measure of segment AC if it is given as 14?

Back

The measure of segment AC is 14, indicating the total length of the segment.

Front

How do you find the value of x in relation to the length of segment VU?

Back

To find the value of x in relation to the length of segment VU, set up an equation based on the properties of the segments and solve for x.