Obtén la segunda derivada de la siguiente función: y = x y=\sqrt{x} y = x <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

y ′ ′ = − 1 2 x x y''=-\frac{1}{2x\sqrt{x}} y ′ ′ = − 2 x x <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1

y ′ ′ = 1 2 x y''=\frac{1}{2\sqrt{x}} y ′ ′ = 2 x <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1

y ′ ′ = − 1 2 x y''=-\frac{1}{2\sqrt{x}} y ′ ′ = − 2 x <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1

y ′ ′ = 1 2 x x y''=\frac{1}{2x\sqrt{x}} y ′ ′ = 2 x x <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1

Concepto de derivada:

Recta tangente que permite calcular la velocidad en un punto exacto de la función

Recta secante que permite calcular la velocidad promedio de una función

Recta tangente que permite calcular la velocidad en dos puntos de la función

Recta secante que permite calcular la velocidad en un punto exacto de la función

Si analizamos la monotonía de la siguiente función y los extremos relativos...

Creciente: (-3, -2) U (0, 1). Decreciente: (-2, 0) Máximo: (-2, 2). Mínimo: (0, -2)

Creciente: (-2, 0). Decreciente: (-3, -2) U (0, 1) Máximo: (-2, 2). Mínimo: (0, -2)

Creciente: (-3, -2) U (0, 1). Decreciente: (-2, 0) Mínimo: (-2, 2). Máximo: (0, -2)

Creciente: (-2, 0). Decreciente: (-3, -2) U (0, 1) Mínimo: (-2, 2). Máximo: (0, -2)

Del gráfico de la función, determina los mínimos indicando sus coordenadas:

Mínimos locales: (1. 10), (4, 20), (8, 0) Mínimo absoluto: (8, 0)

Máximos locales: (1. 10), (4, 20), (8, 0) Máximo absoluto: (4, 20)

Máximos locales: (-1, 40), (3, 30), (6, 50) Máximo absoluto: (6, 50)

Máximos locales: (-1, 40), (3, 30), (6, 50) Máximo absoluto: (3, 30)

Al aplicar el criterio de la segunda derivada podemos encontrar en una función:

Los puntos de inflexión de la función

Los intervalos de decrecimiento de una función

Los intervalos de crecimiento de una función

Encuentra extremos relativos de la siguiente función. 2x 3 - 3x 2

máximo relativo x = 0 ; mínimo relativo x = 1

máximo relativo x = 3 ; mínimo relativo x = 1

máximo relativo x = 0 ; mínimo relativo x = 2

máximo relativo x = -2 ; mínimo relativo x = 1

How many extrema are there in this graph?

3 increasing intervals, 2 decreasing intervals

2 increasing intervals, 3 decreasing intervals

What can you conclude from this number line?

you will have a profitable year

examen cálculo 3er parcial

10th - 12th Grade

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38 Qs

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examen cálculo 3er parcial

Quiz

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•

10th - 12th Grade

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Practice Problem

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Hard

Alejandro Campa

Used 2+ times

FREE Resource

38 questions

Show all answers

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Calcula la derivada de la función:
f(x)=7

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Calcula la derivada de la función:
f(x)=3x +5

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Calcula la derivada de la función:
f(x) = x⁷

x⁶

7x⁶

7x⁵

7x⁷

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

La derivada de la función $f\left(x\right)=2x^2-1$ es

$4x$

$4$

$4x^2$

$2x$

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

La derivada de la función f(x)=5x³-4x² es

-45x²+5

15x²- 8x

-15x²+4x

15x-8x

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

¿Cuál es la derivada del producto?

f' · g'

f' · g - f · g'

f' · g + f · g'

La sabía

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

f(x) = (3x-2)(2x+3)

12x+5

12x

12x-5

6x+4

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examen cálculo 3er parcial

38 questions

Calcula la derivada de la función:
f(x)=7

Calcula la derivada de la función:
f(x)=3x +5

Calcula la derivada de la función:
f(x) = x⁷

La derivada de la función $f\left(x\right)=2x^2-1$ es

La derivada de la función f(x)=5x³-4x² es

¿Cuál es la derivada del producto?

f(x) = (3x-2)(2x+3)

¿Que representa la derivada?

¿Que signo expresa cuando una ecuación ya esta derivada?

Calcula la derivada de:

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Discover more resources for Mathematics

examen cálculo 3er parcial

38 questions

Calcula la derivada de la función:f(x)=7

Calcula la derivada de la función:f(x)=3x +5

Calcula la derivada de la función:f(x) = x7

La derivada de la función f(x)=2x2−1f\left(x\right)=2x^2-1f(x)=2x2−1 es

La derivada de la función f(x)=5x3-4x2 es

¿Cuál es la derivada del producto?

f(x) = (3x-2)(2x+3)

¿Que representa la derivada?

¿Que signo expresa cuando una ecuación ya esta derivada?

Calcula la derivada de:

Create a free account and access millions of resources

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

Calcula la derivada de la función:
f(x)=7

Calcula la derivada de la función:
f(x)=3x +5

Calcula la derivada de la función:
f(x) = x⁷

La derivada de la función $f\left(x\right)=2x^2-1$ es

La derivada de la función f(x)=5x³-4x² es