elektrokimia

elektrokimia

12th Grade

15 Qs

quiz-placeholder

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elektrokimia

elektrokimia

Assessment

Quiz

Chemistry

12th Grade

Practice Problem

Medium

Created by

kiki sukirman

Used 4+ times

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15 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 4 pts

Bilangan oksidasi atom S yang paling tinggi terdapat pada….

SO2

S2O32-

S4O62-

SO42-

H2S


2.

MULTIPLE CHOICE QUESTION

2 mins • 4 pts

Perhatikan potensial elektroda berikut.

Cu2+ I Cu Eo = + 0,34 V

Ag+ I Ag Eo = +0,80 V

Notasi sel:

Cu(s)ǀ Cu2+(aq) ∥ Ag+(aq)ǀAg(s)

Memiliki potensial sel sebesar….

0,06 volt

0,46 volt

0,56 volt

1,14 volt

1,26 volt

3.

MULTIPLE CHOICE QUESTION

3 mins • 4 pts

Diketahui data potensial elektroda berikut

Ag+ + e- → Ag Eo = + 0,80 V

Mg2+ + 2e- → Mg Eo = -2,37 V

ln3+ + 3e- → ln Eo = -0,34 V

Mn2+ + 2e- → Mn Eo = -1,20 V

Zn2+ + 2e- → Zn Eo = -0,76 V

Pasangan sel berikut yang memberikan perbedaan potensial sebesar +1,14 Volt adalah….

Ag ǀ Ag+ ∥ Zn2+ǀ Zn

Mn ǀ Mn2+ ∥ Mg2+ǀ Mg

Mn ǀ Mn2+ ∥ Ag+ǀ Ag

Mg ǀ Mg2+ ∥ Ag+ǀ Ag

In ǀ In3+ ∥ Ag+ǀ Ag

4.

MULTIPLE CHOICE QUESTION

45 sec • 4 pts

Sel volta mengubah energi …. Menjadi energi ….

Listrik → potensial

Listrik → kinetic

Listrik → kimia

Kimia → listrik

Kimia → kinetic

5.

MULTIPLE CHOICE QUESTION

1 min • 4 pts

Diketahui :

Sn2+(aq) + 2e- → Sn(s) Eo = -0.04 V

Ag+(aq) + e- → Ag(s)

Eo = 0.80 V

Suatu sel volta yang terdiri :

Sn / Sn2+ ║Ag+ / Ag

Akan menghasilkan potensial sel sebesar …

+0.76 volt

+1.64 volt

+0.94 volt

+1.56 volt

+0.84 volt

6.

MULTIPLE CHOICE QUESTION

1 min • 4 pts

Media Image

Perhatikan gambar rangkaian sel volta berikut

Berdasarkan gambar rangkaian tersebut, diagram sel

yang tepat adalah…

Mg2+ | Mg || Cu | Cu2+

Mg2+ | Mg || Cu2+ | Cu

Mg | Mg2+ || Cu | Cu2+

Mg | Mg2+ || Cu2+ | Cu

Cu2+ | Cu || Mg | Mg2+

7.

MULTIPLE CHOICE QUESTION

2 mins • 4 pts

Pada elektrolisis larutan tembaga (II) sulfat dengan elektrode tembaga, di anode

terjadi reaksi…

Cu2+ (aq) + 2e- → Cu(s)

Cu(s) → Cu2+ (aq) + 2e-

2H2O (l) + 2e- → H2 (g) + OH-

(aq)

2H2O (l) → 4H+

(aq) + O2 (g) + 4e-

SO4

2-

(aq) +H2O (l) → H2SO4 (aq)

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