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molar mass

Authored by irene aquino

Chemistry, Science

11th Grade

molar mass
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5 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the molar mass of PbSO4?

303.27 g/mol

255.27 g/mol

163.87 g/mol

372.27 g/mol

Answer explanation

To calculate molar mass:

1. Use the periodic table to find the atomic mass of each element in a particle.

2. Multiply each atomic mass by the number of atoms of each element in the particle.

  1. 3. Find the sum, then change units to g/mol.

    Round to 2 decimal places (closest hundredth).

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

(Hint: write out how you would solve the problem first on paper before choosing an answer.) 

How would you set up the problem: if you have a sample of 2.50 g of sodium (Na), how many moles of Na do you have?

2.50g Na ×22.99 mol Na1 g Na=2.50g\ Na\ \times\frac{22.99\ mol\ Na}{1\ g\ Na}=  

2.50 g Na ×1 mol Na22.99 g Na=2.50\ g\ Na\ \times\frac{1\ mol\ Na}{22.99\ g\ Na}=  

2.50 g Na ×22.99 g Na1 mol Na=2.50\ g\ Na\ \times\frac{22.99\ g\ Na}{1\ mol\ Na}=  

2.50 g Na ×1 g Na 22.99 mol Na=2.50\ g\ Na\ \times\frac{1\ g\ Na\ }{22.99\ mol\ Na}=  

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the molar mass of Al2(CO3)3?

113.97 g/mol

137.99 g/mol

233.99 g/mol

185.99 g/mol

Answer explanation

To calculate molar mass:

1. Use the periodic table to find the atomic mass of each element in a particle.

2. Multiply each atomic mass by the number of atoms of each element in the particle.

  1. 3. Find the sum, then change units to g/mol.

    Round to 2 decimal places (closest hundredth).

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How would you set up the problem if you want to find the mass, in grams, of 0.55 moles of silicon?

0.55 mol Si × 28.09 g Si1 mol Si = 0.55\ mol\ Si\ \times\ \frac{28.09\ g\ Si}{1\ mol\ Si}\ =\  

0.55 mol Si ×1 g Si 28.09 mol Si=0.55\ mol\ Si\ \times\frac{1\ g\ Si\ }{28.09\ mol\ Si}=  

0.55 mol Si ×28.09 mol Si1 g Si=0.55\ mol\ Si\ \times\frac{28.09\ mol\ Si}{1\ g\ Si}=  

0.55 mol Si ×1 mol Si28.09 g Si=0.55\ mol\ Si\ \times\frac{1\ mol\ Si}{28.09\ g\ Si}=  

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How would you set up the problem if you have 3.80 moles of calcium (Ca), and you are trying to determine how many atoms of calcium you have?

3.80 mol Ca ×40.08 g Ca1 mol Ca=3.80\ mol\ Ca\ \times\frac{40.08\ g\ Ca}{1\ mol\ Ca}=  

3.80 mol Ca ×6.022 x 1023 atoms Ca1 mol Ca=3.80\ mol\ Ca\ \times\frac{6.022\ x\ 10^{23\ }atoms\ Ca}{1\ mol\ Ca}=  

3.80 mol Ca ×1 g Ca40.08 mol Ca=3.80\ mol\ Ca\ \times\frac{1\ g\ Ca}{40.08\ mol\ Ca}=  

3.80 mol Ca ×1 atoms Ca6.022 x 1023 mol Ca=3.80\ mol\ Ca\ \times\frac{1\ atoms\ Ca}{6.022\ x\ 10^{23}\ mol\ Ca}=  

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