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Related Rates

Authored by Helena McCalla

Mathematics

12th Grade

CCSS covered

Used 2+ times

Related Rates
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11 questions

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1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

A ladder is 10 meters long and is leaning against a wall. If the bottom of the ladder is sliding away from the wall at a rate of 2 m/s, how fast is the top of the ladder sliding down the wall when the bottom of the ladder is 6 meters from the wall?

-1 m/s

2 m/s

3 m/s

0.5 m/s

Tags

CCSS.HSA.CED.A.2

CCSS.HSG.SRT.C.8

2.

OPEN ENDED QUESTION

5 mins • 5 pts

A spherical ballon is being inflated at a rate of 100 cm3sec⁡.100\ \frac{cm^3}{\sec}. How fast is the radius of the ballon increasing when the diameter is 50 cm?50\ cm?

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3.

OPEN ENDED QUESTION

5 mins • 5 pts

A 13−foot13-foot ladder is leaning against a wall when its base starts to slide away from the wall. By the time its base is 12 ft12\ ft from the wall, the base is moving at the rate of 5 ftsec⁡.5\ \frac{ft}{\sec}. How fast is the top of the ladder sliding down the wall then?

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4.

OPEN ENDED QUESTION

5 mins • 5 pts

All edges of a cube are expanding at a rate of 3 centimeters per second. How fast is the volume changing each edge is 1 centimeter.

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5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A balloon is being inflated and its volume is increasing at a rate of 100 cubic centimeters per second. How fast is the radius of the balloon increasing when the radius is 5 centimeters? (Use the formula for the volume of a sphere: V=43πr3V = \frac{4}{3}\pi r^3 )

14π\frac{1}{4\pi} cm/s

25π\frac{2}{5\pi} cm/s

54π\frac{5}{4\pi} cm/s

35π\frac{3}{5\pi} cm/s

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find dy/dx
xy+y2=2

-y/(x+2y)
y/(x+2y)
-3y/x
-3x/y

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Given: Water slowly evaporates from a circular shaped puddle. The area of the puddle decreases at a rate of  36π in2hr36\pi\ \frac{in^2}{hr}  . Assuming the puddle retains its circular shape, at what rate is the radius of the puddle changing when the radius is 5 in?

drdt=−1.8 inhr\frac{dr}{dt}=-1.8\ \frac{in}{hr}

drdt=−3.6 inhr\frac{dr}{dt}=-3.6\ \frac{in}{hr}

drdt=−3625 inhr\frac{dr}{dt}=-\frac{36}{25}\ \frac{in}{hr}

drdt=6 inhr\frac{dr}{dt}=6\ \frac{in}{hr}

Tags

CCSS.HSA.CED.A.2

CCSS.HSG.GMD.A.1

CCSS.HSA.REI.A.1

CCSS.HSA.SSE.A.1

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