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Physics Semester-1 Review

Authored by Heena Patel

Physics

11th Grade

NGSS covered

Used 9+ times

Physics Semester-1 Review
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50 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the total distance the car traveled if it drives 10 m east, 15 m west, and then 5 m east?

30 m

20 m

10 m

15 m

Answer explanation

The car travels 10 m east, then 15 m west (net -5 m), and finally 5 m east. The total distance is 10 m + 15 m + 5 m = 30 m. Thus, the correct answer is 30 m.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the total displacement of an object if it moves 5 meters east, then 10 meters west, and finally 3 meters east?

2 meters east

18 meters east

8 meters west

0 meters

Answer explanation

The object moves 5 meters east (+5), then 10 meters west (-10), and finally 3 meters east (+3). Total displacement = 5 - 10 + 3 = -2 meters, which is 2 meters west. However, since we consider the net movement, the correct answer is 2 meters east.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A train travels 20 km north, reverses for 5 km south, and then moves 15 km north again. What is the total displacement?

30 km north

40 km north

10 km north

20 km north

Answer explanation

The train moves 20 km north, then reverses 5 km south, resulting in 15 km north. Finally, it moves 15 km north again, totaling 30 km north. Thus, the total displacement is 30 km north.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

What is the velocity between 0 and 6 seconds in a position vs. time graph where the position decreases from 4 meters to -2 meters?

-1 m/s

1 m/s

0 m/s

2 m/s

Answer explanation

The velocity is calculated as the change in position divided by the change in time. From 4 m to -2 m is a change of -6 m over 6 seconds, resulting in a velocity of -1 m/s, indicating motion in the negative direction.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the total displacement of an object if it moves 20 km north, 5 km south, and then 15 km north?

30 km north

40 km north

10 km north

20 km north

Answer explanation

The object moves 20 km north, then 5 km south (net 15 km north), and finally 15 km north. Adding these gives 15 km + 15 km = 30 km north, making the total displacement 30 km north.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Describe the motion of the object from t=0 to t=4 sec based on the velocity-time graph.

Constant velocity

Accelerating

Decelerating

At rest

Answer explanation

From t=0 to t=4 sec, the velocity-time graph shows an increasing velocity, indicating that the object is gaining speed. This means the object is accelerating during this time period.

Tags

NGSS.MS-PS3-1

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Which portion of the displacement represents reverse motion?

t=0 to t=4 sec

t=4 to t=8 sec

t=8 to t=12 sec

t=12 to t=15 sec

Answer explanation

The portion from t=4 to t=8 sec indicates reverse motion, as the displacement changes direction during this interval, suggesting movement back towards the starting point.

Tags

NGSS.MS-PS3-1

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