Word Math Problem/SAT

Adam is 7 years older than Han. In 4 years, Adam will be twice as old as Han. How many years old is Adam now?

• 10

• 3

• 13

• 8

Adam is 7 years older than Han. In 4 years, Adam will be twice as old as Han. Which equation would you use to solve this problem?

• (H+7)+4=2×(H+4)

• (H+7)=2×(H+4)

• A= H+7

• A=2(H+7)

Adam is 7 years older than Han. In 4 years, Adam will be twice as old as Han In this problem, what does the phrase 'In 4 years' mean?

• Adam's age will be twice Han's current age.

• Adam's age will be 7 years more than Han's age.

• Both Adam and Han will be 4 years older.

• Adam's age will be four times Han's age.

One number is 4 times another number. The sum of these two numbers is 60. What is the larger of the two numbers?

• 12

• 24

• 36

• 48

One number is 4 times another number. The sum of these two numbers is 60. Which of the following represents the equation for these numbers?

• x+4=60

• x+4x=60

• 4x=60

• x+4x=4

The sum of three consecutive integers is 105. What is the largest of these three integers?

• 32

• 34

• 36

• 35

The sum of three consecutive integers is 105. Which of the following represents the equation for these integers?

• x+(x+1)+(x+2)=105

• x+(x+2)+(x+3)=105

• x+(x+1)+(x+3)=105

• 3x+3=105

Arun is x years old now.what was his age 5 years ago

• 5x

• 5-x

• x-5

• x+5

Tags

CCSS.6.EE.A.2

CCSS.6.EE.B.6

The sum of the ages of a father and his son is 70. Five years ago, the father was 3 times as old as his son. How old are the father and son now?

• Father is 40 years old and son is 5 years old.

• Father is 35 years old and son is 10 years old.

• Father is 30 years old and son is 15 years old.

• Father is 25 years old and son is 20 years old.

A grocery store has monthly fixed costs of $4,000 and monthly salary costs of $3,500 for each employee. If the store maintains a total of x employees during a certain year, which of the following equations represents the total cost c, in dollars, of running the store for that year?

• c=12(5,000+3,000x)

• c=12(4,000+3,500x)

• c=12(3,000+2,500x

• c=5,000+12.3,000x