Practice Problem: Dilution Calculations

The video tutorial covers solving dilution problems using the formula M1V1 = M2V2. It explains how to calculate the concentration of a diluted solution and determine the volume of a solution needed for dilution. Three examples are provided: diluting sodium chloride, preparing a diluted HCL solution, and determining the volume of NaOH required for a specific concentration. The tutorial emphasizes understanding the relationship between initial and final concentrations and volumes.

What is the main equation used to solve dilution problems?

• M1V1 = M2V2

• C1V1 = C2V2

• P1V1 = P2V2

• D1V1 = D2V2

In the first problem, what is the initial concentration of the sodium chloride solution?

• 2.36 molar

• 1.80 molar

• 5.00 molar

• 0.850 molar

What is the final concentration of the sodium chloride solution after dilution?

• 5.00 molar

• 0.850 molar

• 1.80 molar

• 2.36 molar

In the second problem, what is the concentration of the stock HCL solution?

• 1.59 molar

• 0.10 molar

• 0.45 molar

• 0.12 molar

What is the volume of the diluted HCL solution prepared in the second problem?

• 11 milliliters

• 41 milliliters

• 5 liters

• 0.314 liters

In the third problem, what is the desired concentration of the diluted NaOH solution?

• 0.45 molar

• 0.10 molar

• 1.59 molar

• 0.12 molar

How much of the stock NaOH solution is needed to prepare the diluted solution in the third problem?

• 0.314 liters

• 41 milliliters

• 5 liters

• 11 milliliters