Electrophilic Aromatic Substitution
Interactive Video
•
Chemistry, Science, Physics
•
11th Grade - University
•
Hard
Wayground Content
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the main reason aromatic systems prefer substitution over addition reactions?
Aromatic systems are less stable than aliphatic systems.
Aromatic systems have no pi bonds.
Aromatic systems aim to maintain their stability.
Aromatic systems do not interact with electrophiles.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In electrophilic aromatic substitution, what is the intermediate formed after the electrophile attaches to the benzene ring?
Carbanion
Radical ion
Arenium ion
Carbocation
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How is aromaticity restored in the benzene ring during electrophilic aromatic substitution?
By removing all pi bonds.
By adding a halide ion.
By adding a new electrophile.
By forming a new pi bond after proton extraction.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which of the following is NOT a characteristic of the arenium ion intermediate?
It has delocalized positive charge.
It is sp3 hybridized.
It is a stable intermediate.
It has high electron density.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why is the first step of electrophilic aromatic substitution considered the rate-determining step?
It involves the formation of a stable intermediate.
It is an exothermic process.
It involves breaking aromaticity, which is energetically unfavorable.
It is the fastest step in the reaction.
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the role of a Lewis acid catalyst in halogenation of benzene?
To provide additional electrons.
To consume the reactants.
To increase the temperature of the reaction.
To lower the activation energy of the reaction.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the main reason benzene does not react directly with bromine without a catalyst?
Bromine is not reactive enough.
Breaking aromaticity is too energetically unfavorable.
Benzene lacks pi bonds.
Benzene is too reactive.
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