5.5-5.6 Packet Check

Complete the proof

a

b

c

d

e

f

(2) Given

Corresponding Angles

Alternate Interior Angles

SSA

(3) Given

BD = DE

SAS

Vertical Angles

(1) Given

Tags

CCSS.HSG.SRT.B.5

Complete the proof.

a

b

c

d

e

f

(2) Given

(1) Given

SSS

transitive property

ASA

<DAC = <BAC

AC = AC

∆ADC ≅ ∆ABC

SAS

Tags

CCSS.HSG.SRT.B.5

Complete the proof.

a

b

c

d

e

JM ≅ NM

∆JLM ≅ ∆NLM

⦣JLM  ≅ ⦣NLM

LM ≅ LM

L is the midpoint of JN

JL ≅ NL

Tags

CCSS.HSG.SRT.B.5

Complete the proof.

Be sure to label your diagram on your packet as you go.

a

b

c

d

e

(2) Definition of Angle Bisector

Transitive Property

ASA

(2) Vertical Angles

(1) Given

Reflexive Property

(3) Definition of Angle Bisector

AAS

(3) Vertical Angles

Tags

CCSS.HSG.SRT.B.5

Complete the proof.

Be sure to label the diagram in your packet as you go.

a

b

c

ASA

AAS

Alternate Interior Angles

YZ ≅ YZ

∠WYZ ≅ ∠XYZ

Tags

CCSS.HSG.SRT.B.5

Determine the relationship between each pair of triangles.

a

b

c

d

SAS

AAA

AAS

SSS

HL

ASA

Tags

CCSS.HSG.SRT.B.5

Complete the proof.

Be sure to table the diagram in your packet as you go!

a

b

c

d

e

AAS

SAS

ASA

(3) Corresponding Angles

(3) Alternate Interior Angles

Reflexive Property

(2) Alternate Interior Angles

(2) Corresponding Angles

Given

Tags

CCSS.HSG.SRT.B.5

Complete the proof.

Be sure to label the diagram in your packet as you go!

a

b

c

d

e

ASA

AAS

Reflexive Property

Definition of Bisect

Transitive Property

(3) Given

(1) Given

SAS

Tags

CCSS.HSG.SRT.B.5

Complete the proof.

Label the diagram in your packet as you go!

a

b

c

d

e

h

(1) Given

AAA

Alternate Interior Angles

(3) Given

Definition of Midpoint

ASA

Vertical Angles

SAS

Tags

CCSS.HSG.SRT.B.5

Determine the relationship between the two triangles.

(Type SSS, SAS, ASA, AAS, AAA, or SSA)

Tags

CCSS.HSG.SRT.B.5