5.5-5.6 Packet Check

Complete the proof

a

b

c

d

e

f

Corresponding Angles

SAS

Alternate Interior Angles

BD = DE

(1) Given

Vertical Angles

SSA

(2) Given

(3) Given

Tags

CCSS.HSG.SRT.B.5

Complete the proof.

a

b

c

d

e

f

SAS

<DAC = <BAC

SSS

AC = AC

transitive property

∆ADC ≅ ∆ABC

(2) Given

(1) Given

ASA

Tags

CCSS.HSG.SRT.B.5

Complete the proof.

a

b

c

d

e

JM ≅ NM

⦣JLM  ≅ ⦣NLM

L is the midpoint of JN

∆JLM ≅ ∆NLM

JL ≅ NL

LM ≅ LM

Tags

CCSS.HSG.SRT.B.5

Complete the proof.

Be sure to label your diagram on your packet as you go.

a

b

c

d

e

(2) Definition of Angle Bisector

(3) Definition of Angle Bisector

(1) Given

Transitive Property

Reflexive Property

ASA

AAS

(3) Vertical Angles

(2) Vertical Angles

Tags

CCSS.HSG.SRT.B.5

Complete the proof.

Be sure to label the diagram in your packet as you go.

a

b

c

YZ ≅ YZ

AAS

ASA

∠WYZ ≅ ∠XYZ

Alternate Interior Angles

Tags

CCSS.HSG.SRT.B.5

Determine the relationship between each pair of triangles.

a

b

c

d

AAA

AAS

SAS

ASA

HL

SSS

Tags

CCSS.HSG.SRT.B.5

Complete the proof.

Be sure to table the diagram in your packet as you go!

a

b

c

d

e

SAS

AAS

ASA

(2) Corresponding Angles

Given

(3) Alternate Interior Angles

(3) Corresponding Angles

(2) Alternate Interior Angles

Reflexive Property

Tags

CCSS.HSG.SRT.B.5

Complete the proof.

Be sure to label the diagram in your packet as you go!

a

b

c

d

e

Definition of Bisect

SAS

Transitive Property

(3) Given

ASA

(1) Given

Reflexive Property

AAS

Tags

CCSS.HSG.SRT.B.5

Complete the proof.

Label the diagram in your packet as you go!

a

b

c

d

e

h

Vertical Angles

(3) Given

Alternate Interior Angles

SAS

AAA

ASA

(1) Given

Definition of Midpoint

Tags

CCSS.HSG.SRT.B.5

Determine the relationship between the two triangles.

(Type SSS, SAS, ASA, AAS, AAA, or SSA)

Tags

CCSS.HSG.SRT.B.5