5.5-5.6 Packet Check

Complete the proof

a

b

c

d

e

f

(1) Given

BD = DE

Vertical Angles

(2) Given

SAS

Alternate Interior Angles

(3) Given

Corresponding Angles

SSA

Complete the proof.

a

b

c

d

e

f

∆ADC ≅ ∆ABC

<DAC = <BAC

ASA

SSS

AC = AC

transitive property

(1) Given

(2) Given

SAS

Complete the proof.

a

b

c

d

e

LM ≅ LM

∆JLM ≅ ∆NLM

L is the midpoint of JN

⦣JLM  ≅ ⦣NLM

JM ≅ NM

JL ≅ NL

Complete the proof.

Be sure to label your diagram on your packet as you go.

a

b

c

d

e

(3) Definition of Angle Bisector

(1) Given

(2) Vertical Angles

(2) Definition of Angle Bisector

ASA

(3) Vertical Angles

Transitive Property

AAS

Reflexive Property

Complete the proof.

Be sure to label the diagram in your packet as you go.

a

b

c

AAS

YZ ≅ YZ

ASA

Alternate Interior Angles

∠WYZ ≅ ∠XYZ

Determine the relationship between each pair of triangles.

a

b

c

d

AAS

ASA

SAS

HL

SSS

AAA

Complete the proof.

Be sure to table the diagram in your packet as you go!

a

b

c

d

e

AAS

(3) Alternate Interior Angles

Reflexive Property

SAS

(3) Corresponding Angles

(2) Alternate Interior Angles

(2) Corresponding Angles

ASA

Given

Complete the proof.

Be sure to label the diagram in your packet as you go!

a

b

c

d

e

AAS

(3) Given

Definition of Bisect

Reflexive Property

SAS

Transitive Property

(1) Given

ASA

Complete the proof.

Label the diagram in your packet as you go!

a

b

c

d

e

h

SAS

Vertical Angles

AAA

(3) Given

Definition of Midpoint

Alternate Interior Angles

(1) Given

ASA

Determine the relationship between the two triangles.

(Type SSS, SAS, ASA, AAS, AAA, or SSA)