Equation of Circle

(x - h)² + (y - k)² = r²; x² + y² + ax + by + c = 0

(x - h)² + (y - k)² = r²; Ax + By + C = 0

Ax² + By² + Cx + Dy + E = 0; (x - h)² + (y - k)² = r²

Ax + By + C = 0; (x - h)² + (y - k)² = r²

30

20

-30

-20

Centre = (2, 6)

Centre = (2, -4)

Centre = (-2, 4)

Centre = (-2, -4)

Centre = (2, 4)

$$option\ 2:\ (x+1)^2+(y-2)^2=2^2$$

Option 3: $$x^2 + 2x + y^2 - 4y + 1 = 0$$

Option 1 and Option 3

Option 2 and Option 3

Option 1: $$(x - 1)^2 + (y - 2)^2 = 2^2$$

The point (1, 2√2) lies on the circle.

The point (1, 2√2) does not lie on the circle.

The circle does not pass through the origin.

The circle's radius is not defined.

$$(x - 6)^2 + (y - 4)^2 = 25$$

$$(x + 6)^2 + (y + 4)^2 = 25$$

$$(x - 6)^2 + (y - 4)^2 = 27$$

$$(x + 6)^2 + (y + 4)^2 = 3\sqrt{3}$$

$$x^2+y^2=2^2$$

$$(x-5)^2+(y-6)^2=9$$

$$x^2+y^2+2gx+2fy+c=0$$

$$(x+6)^2+(y+5)^2=r^2$$

(4, 3)

(-3, -4)

(3, 4)

(-4, -3)

$$(x+5)^2+(y-2)^2=121$$

$$(x-5)^2+(y+2)^2=11$$

$$(x+2)^2+(y-5)^2=121$$

$$(x-2)^2+(y+5)^2=22^2$$