
Unit 7 Progress Check
Quiz
•
Other
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12th Grade
•
Practice Problem
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Hard
Emma C
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12 questions
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1.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
The mean age of the employees at a large corporation is 35.2 years, and the standard deviation is 9.5 years. A random sample of 4 employees will be selected.
What are the mean and standard deviation of the sampling distribution of the sample mean for samples of size 4 ?
The mean is 35.2, and the standard deviation is 9.5.
The mean is 35.2, and the standard deviation is 9.5/4.
The mean is 35.2, and the standard deviation is 9.5/2.
The mean is 35.2/4, and the standard deviation is 9.5/4.
The mean is 35.2/2, and the standard deviation is 9.5/2.
2.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
The distribution of the commute times for the employees at a large company has mean 22.4 minutes and standard deviation 6.8 minutes. A random sample of n employees will be selected and their commute times will be recorded.
What is true about the sampling distribution of the sample mean as n increases from 2 to 10?
The mean increases, and the variance increases.
The mean increases, and the variance decreases.
The mean does not change, and the variance does not change.
The mean does not change, and the variance increases.
The mean does not change, and the variance decreases.
3.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
The distribution of the number of siblings for students at a large high school is skewed to the right with mean 1.8 siblings and standard deviation 0.7 sibling. A random sample of 100 students from the high school will be selected, and the mean number of siblings in the sample will be calculated.
Which of the following describes the sampling distribution of the sample mean for samples of size 100 ?
Skewed to the right with standard deviation 0.7 sibling
Skewed to the right with standard deviation less than 0.7 sibling
Skewed to the right with standard deviation greater than 0.7 sibling
Approximately normal with standard deviation 0.7 sibling
Approximately normal with standard deviation less than 0.7 sibling
4.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
The distribution of height for a certain population of women is approximately normal with mean 65 inches and standard deviation 3.5 inches. Consider two different random samples taken from the population, one of size 5 and one of size 85.
Which of the following is true about the sampling distributions of the sample mean for the two sample sizes?
Both distributions are approximately normal with mean 65 and standard deviation 3.5.
Both distributions are approximately normal. The mean and standard deviation for size 5 are both less than the mean and standard deviation for size 85.
Both distributions are approximately normal with the same mean. The standard deviation for size 5 is greater than that for size 85.
Only the distribution for size 85 is approximately normal. Both distributions have mean 65 and standard deviation 3.5.
Only the distribution for size 85 is approximately normal. The mean and standard deviation for size 5 are both less than the mean and standard deviation for size 85.
5.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
The distribution of wait times for customers at a certain department of motor vehicles in a large city is skewed to the right with mean 23 minutes and standard deviation 11 minutes. A random sample of 50 customer wait times will be selected. Let x¯W represent the sample mean wait time, in minutes. Which of the following is the best interpretation of P(x¯W>25)≈0.10 ?
For a random sample of 50 customer wait times, the probability that the total wait time will be greater than 25 minutes is approximately 0.10.
For a randomly selected customer from the population, the probability that the total customer wait time will be greater than 25 minutes is approximately 0.10.
For a randomly selected customer from the population, the probability that the sample mean customer wait time will be greater than 25 minutes is approximately 0.10.
For a random sample of 50 customer wait times, the probability that the sample mean customer wait time will be greater than 23 minutes is approximately 0.10.
For a random sample of 50 customer wait times, the probability that the sample mean customer wait time will be greater than 25 minutes is approximately 0.10.
6.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
A sports magazine reports that the mean number of hot dogs sold by hot dog vendors at a certain sporting event is equal to 150. A random sample of 50 hot dog vendors was selected, and the mean number of hot dogs sold by the vendors at the sporting event was 140.
For samples of size 50, which of the following is true about the sampling distribution of the sample mean number of hot dogs sold by hot dog vendors at the sporting event?
For all random samples of 50 sporting events, the sample mean will be 150 hot dogs.
For all random samples of 50 hot dog vendors, the sample mean will be 140 hot dogs.
The mean of the sampling distribution of the sample mean is 150 hot dogs.
The mean of the sampling distribution of the sample mean is 140 hot dogs.
All random samples of 50 hot dog vendors will have a sample mean within 10 hot dogs of the population mean.
7.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
A certain company produces fidget spinners with ball bearings made of either plastic or metal. Under standard testing conditions, fidget spinners from this company with plastic bearings spin for an average of 2.7 minutes, while those from this company with metal bearings spin for an average of 4.2 minutes. A random sample of three fidget spinners with plastic bearings is selected from company stock, and each is spun one time under the same standard conditions; let x¯1 represent the average spinning time for these three spinners. A random sample of seven fidget spinners with metal bearings is selected from company stock, and each is likewise spun one time under standard conditions; let x¯2 represent the average spinning time for these seven spinners. What is the mean μ(x¯1−x¯2) of the sampling distribution of the difference in sample means x¯1−x¯2 ?
3(2.7) - 7(4.2) = -21.3
3-7 = -4
2.7 - 4.2 = -1.5
2.7/3 - 4.2/7 = 0.3
4.2 - 2.7 = 1.5
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