What is the first step in simplifying $$\frac{7}{9a^2}-\frac{8}{6a}$$ ?

Change to: $$\frac{14}{18a^2}-\frac{24a}{18a^2}$$

Change to: $$\frac{7}{18a^2}-\frac{8}{18a^2}$$

Change to: $$\frac{7}{9a^2}-\frac{24}{9a^2}$$

Change to: $$\frac{7}{9a^2}-\frac{8}{9a^2}$$

What is the first step in simplifying: $$\frac{4}{x+3}+\frac{8}{x+5}$$ ?

Change to: $$\frac{4\left(x+5\right)}{\left(x+3\right)\left(x+5\right)}+\frac{8\left(x+3\right)}{\left(x+3\right)\left(x+5\right)}$$

Change to: $$\frac{20}{x+15}+\frac{24}{x+15}$$

Change to: $$\frac{20x}{x^2+15}+\frac{24x}{x^2+15}$$

Change to: $$\frac{20}{\left(x+3\right)\left(x+5\right)}+\frac{24}{\left(x+3\right)\left(x+5\right)}$$

$4.3 factoring and fraction review for identities$

4.3 factoring and fraction review for identities

9th - 12th Grade

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20 Qs

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$4.3 factoring and fraction review for identities$

4.3 factoring and fraction review for identities

Quiz

•

Mathematics

•

9th - 12th Grade

•

Practice Problem

•

Easy

•

CCSS

HSA.APR.C.4, HSA.APR.D.7, 7.EE.B.4A

Standards-aligned

Erin Martin

Used 2+ times

FREE Resource

20 questions

Show all answers

(r² + q²) (r² - q²)

(r² - q²) (r² - q²)

(r + q) (r - q)

Can't factor using Diff. of Squares

Tags

CCSS.HSA.APR.C.4

MATH RESPONSE QUESTION

2 mins • 1 pt

Mathematical Equivalence

Tags

CCSS.HSA.APR.C.4

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4.3 factoring and fraction review for identities

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