
Practice Quiz - Thursday 1/22
Authored by Amanda Herring
Chemistry
10th Grade
NGSS covered

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28 questions
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1.
MATCH QUESTION
15 mins • 1 pt
Match the following...
multiplying by the molar mass
You convert moles to particles by...
dividing by the molar mass
You convert moles to grams by...
multiplying my avagadro's constant
You convert grams to moles by...
2.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
What is the molar mass of PbSO4?
303.27 g/mol
255.27 g/mol
163.87 g/mol
372.27 g/mol
Answer explanation
To find the molar mass of PbSO4, sum the atomic masses: Pb (207.2 g/mol) + S (32.07 g/mol) + 4 x O (16.00 g/mol) = 303.27 g/mol. Thus, the correct answer is 303.27 g/mol.
3.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
How many molecules are there in 31.8 moles of water?
5.28 x 10-23
1.91 x 1025
5.28x 10-25
1.91 x 1022
Answer explanation
To find the number of molecules in 31.8 moles of water, multiply by Avogadro's number (6.022 x 10^23). Thus, 31.8 moles x 6.022 x 10^23 molecules/mole = 1.91 x 10^25 molecules, making the correct answer 1.91 x 10^25.
4.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
Determine the mass of 4.20 moles of C6H12
354 g
0.0499 g
337 g
2.53 x 1024 g
Answer explanation
To find the mass of 4.20 moles of C6H12, first calculate its molar mass: C (12.01 g/mol) x 6 + H (1.008 g/mol) x 12 = 84.06 g/mol. Then, multiply by the number of moles: 4.20 moles x 84.06 g/mol = 353.88 g, rounded to 354 g.
5.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
Which of the following dimensional analysis setups will correctly convert 27.76 g of Li to atoms of Li?
A
B
C
D
Answer explanation
To convert grams of Li to atoms, use the molar mass of Li (6.94 g/mol) and Avogadro's number (6.022 x 10^23 atoms/mol). Choice D correctly sets up the conversion: 27.76 g Li x (1 mol Li/6.94 g) x (6.022 x 10^23 atoms/mol).
6.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
What is the mass of 1.2 x 1024 atoms of C?
2.0 grams
24 grams
0.17 grams
1.4 x 1025 grams
Answer explanation
To find the mass of 1.2 x 10^24 atoms of carbon (C), use the molar mass of carbon (12 g/mol). First, calculate moles: 1.2 x 10^24 atoms / 6.022 x 10^23 atoms/mol = 2 moles. Then, mass = 2 moles x 12 g/mol = 24 grams.
7.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
Calculate the number of atoms in 0.0340 g Zn.
5.20 x 10-4 atoms Zn
3.13 x 1023 atoms Zn
3.13 x 1020 atoms Zn
2.05 x 1022 atoms Zn
Answer explanation
To find the number of atoms in 0.0340 g of Zn, first calculate moles: 0.0340 g / 65.38 g/mol = 0.000519 moles. Then, multiply by Avogadro's number (6.022 x 10^23): 0.000519 moles x 6.022 x 10^23 = 3.13 x 10^20 atoms Zn.
Tags
NGSS.HS-PS1-7
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