Factoring Polynomials and the Zero Product Property

What is the first step in solving 
(x + 2)(x - 3) = 0      ?

• Plug in zero for x
• Solve for x
• FOIL
• Set each binomial factor equal to zero

Tags

CCSS.HSA-REI.B.4B

• x=0

• x=5

• x=2

• x= -5

Tags

CCSS.6.EE.B.7

Solve for x

x+5=0

• x=0

• x=5

• x=2

• x= -5

Tags

CCSS.6.EE.B.7

• x=0

• x=5

• x=2

• x= -5

Tags

CCSS.6.EE.B.7

• x=0

• x=5

• x=2

• x= -5

Tags

CCSS.6.EE.B.7

• x=0

• x=4

• x= -4

• x= 1/4

Tags

CCSS.6.EE.B.7

• TRUE

• FALSE

Tags

CCSS.HSA.REI.A.1

• x=5

  x=2

• x= -5

  x= -2

• x=5

  x= -2

• x= -5

  x=2

Tags

CCSS.HSA-REI.B.4B

• x=4

  x=1

• x= -4

  x= -1

• x= 4

  x= -1

• x= -4

  x=1

Tags

CCSS.HSA-REI.B.4B

Solve for x

x(x-4)=0

• x=0

  x=4

• x=0

  x= -4

• x=1

  x=4

• x= -1

  x= -4

Tags

CCSS.HSA-REI.B.4B