Factoring Completely Lesson

Completely factor 3x⁴ - 15x³ - 18x².

• x²(3x² + 2)(x - 9)

• 3(x² + 1)(x² - 6)

• 3x²(x + 1)(x - 6)

• cannot be factored

Factor 2x³ + 3x² - 2x - 3 completely.

• (2x + 3)(x - 1)(x + 1)

• (2x - 3)(x - 1)(x + 1)

• (2x + 3)(x + 1)(x + 1)

• (2x + 3)(x - 1)(x - 1)

What is the correct factorization of x² - 11x + 18?

• (x + 2)(x - 9)

• (x - 2)(x + 9)

• (x - 2)(x - 9)

• (x + 2)(x + 9)

Factor completely.
2n² + n - 6

• (2n + 7)(n - 9)
• Not factorable
• (2n - 3)(n - 2)
• (2n - 3)(n + 2)

Factor:
x² - 49

• (x + 7)(x - 7)
• (x + 7)²
• (x - 7)²
• (x+7)(x-1)

Tags

CCSS.HSA.APR.C.4

Is x(4x² + 8x + 12) completely factored? If not, what other factoring can occur?

• yes; the polynomial is completely factored.

• no; 4 can be factored from each term of the trinomial

• no; the trinomial 4x² + 8x + 12 can be factored into two binomials.

• no; 4 can be factored from each term of the trinomial and the resulting trinomial can be factored into two binomials.

Factor 
3x² - 75

• 3( x + 5 ) ( x - 5 ) 
• Prime
• ( x + 5 ) ( x - 5 ) 
• 3( x - 5 ) ( x - 5 ) 

Tags

CCSS.HSA.APR.C.4

Factor:  27x³ + 8

• (3x + 2)(9x² - 6x + 4)
• (9x + 2)(3x² + 18x + 4)
• (3x²+4)(9x + 2)
• (27x + 8)(x² - 216x + 64)

Tags

CCSS.HSA.APR.C.4

Factor x³ + 2x² - 49x - 98 

• (x² - 49) (x + 2) 
• (x² - 49) (x + 2) (x + 2) 
• (x + 7) (x - 7) (x + 2) 

What is the correct factorization of -5x² + 9x + 2?

• -(5x - 1)(x + 2)

• -(5x + 1)(x - 2)

• -(5x - 2)(x + 1)

• -(5x + 2)(x - 1)