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Finding Equivalent Fractions Expressions

Authored by Barbara White

Mathematics

6th Grade

CCSS covered

Finding Equivalent Fractions Expressions
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40 questions

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1.

OPEN ENDED QUESTION

3 mins • 1 pt

Read the pattern and find the missing equivalent fraction in each problem. \(\frac{5}{7} = \frac{10}{14} = \frac{15}{21} = \frac{20}{28} = \frac{}{35}\)

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Answer explanation

The missing equivalent fraction is \frac{25}{35} because each numerator is multiplied by 5 to get the next numerator, following the pattern.

Tags

CCSS.3.NF.A.3B

CCSS.4.NF.A.1

2.

OPEN ENDED QUESTION

3 mins • 1 pt

Read the pattern and find the missing equivalent fraction in each problem. \(\frac{1}{3} = \frac{}{9} = \frac{5}{15} = \frac{7}{21} = \frac{9}{27}\)

Evaluate responses using AI:

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Answer explanation

The missing equivalent fraction is 3/9. To find the missing numerator, multiply the denominator by the whole number in the pattern.

Tags

CCSS.3.NF.A.3B

CCSS.4.NF.A.1

3.

OPEN ENDED QUESTION

3 mins • 1 pt

Read the pattern and find the missing equivalent fraction in each problem. \(\frac{9}{2} = \frac{18}{4} = \frac{27}{6} = \frac{36}{8} = \frac{}{10}\)

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Answer explanation

The missing equivalent fraction is \frac{45}{10} because each numerator is multiplied by 9 and the denominator is multiplied by 2 in each step.

Tags

CCSS.3.NF.A.3B

CCSS.4.NF.A.1

4.

OPEN ENDED QUESTION

3 mins • 1 pt

Read the pattern and find the missing equivalent fraction in each problem. \(\frac{8}{5} = \frac{16}{10} = \frac{24}{15} = \frac{}{20} = \frac{40}{25}\)

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Answer explanation

The missing equivalent fraction is 32/20. Each numerator is obtained by multiplying the previous numerator by 2, and the denominator is increased by 5 each time.

Tags

CCSS.3.NF.A.3B

CCSS.4.NF.A.1

5.

OPEN ENDED QUESTION

3 mins • 1 pt

Read the pattern and find the missing equivalent fraction in each problem. \(\frac{1}{6} = \frac{}{12} = \frac{3}{18} = \frac{4}{24} = \frac{5}{30}\)

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Answer explanation

The missing equivalent fraction is 2/12. Each subsequent fraction is obtained by multiplying the numerator and denominator by the next consecutive number starting from 2.

Tags

CCSS.3.NF.A.3B

CCSS.4.NF.A.1

6.

OPEN ENDED QUESTION

3 mins • 1 pt

Read the pattern and find the missing equivalent fraction in each problem. \(\frac{2}{3} = \frac{6}{9} = \frac{10}{15} = \frac{}{21} = \frac{18}{27}\)

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Answer explanation

To find the missing equivalent fraction, continue the pattern by multiplying the numerator and denominator by 3. Therefore, the missing fraction is 15/21.

Tags

CCSS.3.NF.A.3B

CCSS.4.NF.A.1

CCSS.3.NF.A.3A

7.

OPEN ENDED QUESTION

3 mins • 1 pt

Read the pattern and find the missing equivalent fraction in each problem. \(\frac{7}{4} = \frac{14}{8} = \frac{21}{12} = \frac{28}{16} = \frac{}{20}\)

Evaluate responses using AI:

OFF

Answer explanation

The missing equivalent fraction is \frac{35}{20}. Each numerator is obtained by multiplying the previous numerator by 7, and the denominator is increased by 4 each time.

Tags

CCSS.3.NF.A.3B

CCSS.4.NF.A.1

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