Imaginary Number Computation

Find the sum.
(5-2i) + (-7+8i)

• -2+6i
• 12+6i
• -35-16i²
• -35 -16i

Multiply
3i(-2 + 4i)

• -6+12i
• -12-6i
• -2+7i
• 12+6i

The product of (3 -2i) and (7+6i) is

• 21 - 12i
• 9 + 4i
• 33 + 4i
• 21 + 16i

-i(4-9i)

• -13i

• 13i

• 9 - 4i

• -9 - 4i

(10-6i) - (2+3i)

• 12 + 3i
• 8 - 3i
• 8 - 9i
• -9i + 8

(7 - 5i)(7 + 5i)

• 74
• 24
• 49 - 25i
• 49 + 25i

Simplify
3i - (4 + 7i)

• -4 + 10i
• 21 - 12i
• 4 - 10i
• -4 - 4i

What is the value of the expression below?

(2 + 4i) + i(2 + i)

• 3 + 6i

• 2 + 7i

• 7i

• 1 + 6i

Choose the correct answer for the operation pictured.

• 7 - 13i
• 7 - i
• 1 - 13i
• 1 - i

The expression (2 + 3i)² is equal to

• -5
• -5 + 12i
• 13
• 13 + 12i