Quadratic Equation for Projective Motion

What is the Vertex of the graph?

• (-4, -4)

• (0, 0)

• (-8, 0)

• (-2, -3)

The height of an object thrown into the air can be modeled by the formula h(t) = -16t² + 70t + 95, where h(t) is in feet after t seconds.
What is the height of the object after 5 seconds?

• 95 feet
• 45 feet
• 70 feet
• 171.56 feet

A ball is thrown into the air with an upward velocity of 100 ft/s. Its height, h, after t seconds is given by the function
 h = -16t² + 64t + 960.
How many seconds did it take for the ball to reach its maximum height?

• 10 seconds
• 64 seconds
• 960 seconds
• 2 seconds

A ball is thrown into the air with an upward velocity of 100 ft/s. Its height, h, after t seconds is given by the function
 h = -16t² + 64t + 960.
What is the maximum height?

• 960 feet
• 1008 feet
• 1024 feet
• 1152 feet

A ball is thrown into the air with an upward velocity of 100 ft/s. Its height, h, after t seconds is given by the function
 h = -16t² + 64t + 960.
When did the ball hit the ground?

• 10 seconds
• 2 seconds
• 5 seconds
• 7 seconds

What is the y-intercept of the graph?

• -8
• -4
• 1
• 0

Tags

CCSS.HSF-IF.C.7A

What is the Axis of Symmetry?

• x = -8
• x = -4
• x = 4
• x = -2

What are the X-Intercepts, Roots, Zeros, and Solutions?

• {0, -8}
• {8, 0}
• {4, -4}
• {-4, -4}

Tags

CCSS.HSF-IF.C.7A

A diver is standing on a platform above the pool. He jumps form the platform with an initial upward velocity of 8 ft/s. Use the formula
h(t) = −16t² + 8t + 24, where h is his height above the water, t is the time, v is his starting upward velocity, and s is his starting height. How high is the platform?

• .25 ft
• 24 ft
• 25 ft
• 8 ft

A ball is thrown into the air with an upward velocity of 100 ft/s. Its height, h, after t seconds is given by the function
 h = -16t² + 64t + 960.
How many seconds did it take for the ball to reach its maximum height?

• 10 seconds
• 64 seconds
• 960 seconds
• 2 seconds