Solving Systems of Equations Using Elimination or Substitution

Solve by elimination:
4x+9y=28
-4x-y=-28

• (-7,0)
• (6,0)
• (-6,0)
• (7,0)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve by elimination:
-9x-4y=-20

5x+4y=4

• (-4,4)
• (4,4)
• (4,-4)
• (-4,-4)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve by elimination:
-x+2y=17

2x+2y=-10

• ARN
• (-9,4)
• (-9,-4)
• (9,-4)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve by elimination 
-6x+y= -2
-3x-6y= 12

• (2,0)
• no solution 
• (0,-2)
• infinite solutions 

Tags

CCSS.8.EE.C.8B

Solve the system using Multiplication. 
2x + 3y = 12
5x - y = 13

• x = -3, y = -2
• x = 1.5, y = 2
• x = 6, y = 0
• x = 3, y = 2

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system by multiplication.
3x + 2y = 16
7x + y = 19

• (-2,5)
• (-2,-5)
• (2,-5)
• (2,5)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

what does the top equation need to be multiplied by to create a zero pair?

2x - 6y = 20

2x + 5y = -11

• -1

• 1

• -2

• 2

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What is the first step in solving a system of equations by elimination?

• Get both equations in standard form and line up the like terms.
• Get both equations in slope-intercept form.
• Get both equations equal to zero.
• Put the x terms first.

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system by elimination. 
−4x − 4y = 0
4x + 4y = 0 

• (−6, −4) 
• Infinite number of solutions  
• (−6, 10) 
• (6, 4) 

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system:
x + 6y = 17
x - 3y = 8

• (5, 2)
• (11, 1)
• (1, 11)
• no solution

Tags

CCSS.8.EE.C.8B