Money Word Problems with Coins

Money Word Problems with Coins

8th Grade

10 Qs

quiz-placeholder

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Money Word Problems with Coins

Money Word Problems with Coins

Assessment

Quiz

Mathematics

8th Grade

Hard

Created by

Anthony Clark

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Jack has 1 quarter, 4 nickels, and 3 pennies. How much money does he have?

50 cents

68 cents

48 cents

63 cents

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Gabby has 2 quarters, 1 dime, 1 nickel, and 2 pennies. How much money does Gabby have?

67 cents

65 cents

82 cents

50 cents

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

John has 14 coins that have a total of $2.30 The coins are nickels and quarters. How many of each coin does he find?

N + Q = 14

.05N + .25Q = 2.30

N - Q = 14

5N + 25Q = 2.30

N + Q = 2.30

.05N + .25Q = 14

N - Q = 14

.05N + .25Q = 2.30

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

A coin collector has 31 dimes and nickels with a total value of $2.40. How many of each coin does he have?

x + y = 31

10x + 5y = 2.40

x - y = 31

.10x + .05y = 2.40

x + y = 31

.10x + .05y = 2.40

x + y = 2.40

.10x + .05y = 31

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Dennis mowed his next door neighbor’s lawn for a handful of dimes and nickels, 80 coins in all. Upon completing the job he counted out the coins and it came to $6.60. Which system of equations could be used to find the exact number of dimes and nickels?

d + n = 6.60

10d + 5n = 80

d + n = 80

d + n = 6.60

d + n = 80

.10d + .05n = 6.60

d + n = 80

.05d + .10n = 6.60

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Principal Russo has 21 coins totaling $3.45. If she only has dimes and quarters, how many of each type does she have?

D + Q = 21

10D + 25Q = 3.45

D - Q = 21

.10D + .25Q = 3.45

D + Q = 3.45

.10D + .25Q = 21

D + Q = 21

.10D + .25Q = 3.45

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Laura has $.95 in dimes and nickels. She has a total of 11 coins. how many of each type does she have?

d + n = 11

.10d + .05n = 0.95

d + n = 11

10d + 5n = 0.95

d + n = .95

.10d + .05n = 11

d - n = 11

.10d - .05n = 0.95

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