Money Word Problems with Coins

Jack has 1 quarter, 4 nickels, and 3 pennies. How much money does he have?

• 50 cents

• 68 cents

• 48 cents

• 63 cents

Tags

CCSS.4.MD.A.2

Gabby has 2 quarters, 1 dime, 1 nickel, and 2 pennies. How much money does Gabby have?

• 67 cents

• 65 cents

• 82 cents

• 50 cents

Tags

CCSS.4.MD.A.2

John has 14 coins that have a total of $2.30 The coins are nickels and quarters. How many of each coin does he find?

• N + Q = 14

  .05N + .25Q = 2.30

• N - Q = 14

  5N + 25Q = 2.30

• N + Q = 2.30

  .05N + .25Q = 14

• N - Q = 14

  .05N + .25Q = 2.30

Tags

CCSS.8.EE.C.8C

A coin collector has 31 dimes and nickels with a total value of $2.40. How many of each coin does he have?

• x + y = 31

  10x + 5y = 2.40

• x - y = 31

  .10x + .05y = 2.40

• x + y = 31

  .10x + .05y = 2.40

• x + y = 2.40

  .10x + .05y = 31

Tags

CCSS.8.EE.C.8C

Dennis mowed his next door neighbor’s lawn for a handful of dimes and nickels, 80 coins in all. Upon completing the job he counted out the coins and it came to $6.60. Which system of equations could be used to find the exact number of dimes and nickels?

• d + n = 6.60

  10d + 5n = 80

• d + n = 80

  d + n = 6.60

• d + n = 80

  .10d + .05n = 6.60

• d + n = 80

  .05d + .10n = 6.60

Tags

CCSS.8.EE.C.8C

Principal Russo has 21 coins totaling $3.45. If she only has dimes and quarters, how many of each type does she have?

• D + Q = 21

  10D + 25Q = 3.45

• D - Q = 21

  .10D + .25Q = 3.45

• D + Q = 3.45

  .10D + .25Q = 21

• D + Q = 21

  .10D + .25Q = 3.45

Tags

CCSS.8.EE.C.8C

Laura has $.95 in dimes and nickels. She has a total of 11 coins. how many of each type does she have?

• d + n = 11

  .10d + .05n = 0.95

• d + n = 11

  10d + 5n = 0.95

• d + n = .95

  .10d + .05n = 11

• d - n = 11

  .10d - .05n = 0.95

Tags

CCSS.8.EE.C.8C

You have only nickels (x) and dimes (y) in your piggy bank. When you ran the coins through a change counter, it indicated you have 595 cents. Write an equation to represent this situation.

• 5x + 10y = 595

• 10x + 5y = 595

• .05x + .10y = 595

• y = 2x + 595

Tags

CCSS.HSA.CED.A.3

There are approximately 3.1 x 10⁸ people in the United States. If each person has 4.1 x 10¹ coins, how many coins are there altogether?

• 271 x 10¹⁰

• 271 x 10⁹

• 271 x 10¹¹

• 271 x 10⁸

Tags

CCSS.8.EE.A.4

There are approximately 3.1 x 10⁸ people in the United States. If each person has 4.1 x 10¹ coins, how many coins are there altogether?

• Add

• Subtract

• Multiply

• Divide

Tags

CCSS.8.EE.A.4