Rewriting Polynomials Algebra

Factor the following completely:

• (2p²+3)(p+2)

• (2p²+6)(p+4)

• (4p²+3)(p+2)

• (4p²+8p)(3p+6)

Answer explanation

You have to factor this by grouping. The first group is your first two terms and its GCF would be 4p^2, leaving (p+2) inside the parentheses. The second group has a GCF of 3, leaving (p+2). Therefore one binomial is (p+2) and the other is composed of your two GCF's, (4p^2+3)

Factor Completely:
 6x² + 5x - 6

Answer explanation

Start with multiplying a*c, which is 6*-6 in this case, which equals -36. So you need two factors that multiply to -36 and add to 5. It would be -4 and 9.

Rewrite your trinomial as

6x^2+9x-4x-6

You can then use the area model or factor by grouping to find your two binomials

Factor
x² -16x + 48

• (x - 12)(x - 4)

• (x + 6)(x - 8)

• (x + 12)(x - 4)

• (x -16)(x - 3)

-25x²+4x+20x³-5

• (5x²-5)(4x+1)

• 5(x²-1)(4x+5)

• (5x²+1)(4x-5)

• (5x²+1)(4x-1)

Answer explanation

You need to factor by grouping, but first rearrange so your greatest degree (x^3) is written first

Classify the following polynomial

• cubic biniomial

• quadratic polynomial

• linear binomial

• quadratic trinomial

6x² - 11x - 10

• (3x + 5) (2x - 2)

• (2x + 5) (3x - 2)

• (2x - 5) (3x + 2)

• (3x - 5) (2x + 2)

Factor

c² + c - 42

• (c - 6)(c - 7)

• (c + 7)(c + 6)

• (c - 2)(c + 21)

• (c + 7)(c - 6)

Factor: x² + 24x + 144

• (x + 12)²

• (x + 9)²

• (x + 15)²

• (x + 13)²

Tags

CCSS.HSA.APR.C.4

x² + 18x + 81

• (x + 9)(x – 9)

• (x + 18)²

• (x + 9)²

• (x + 6)²

Tags

CCSS.HSA.APR.C.4

Factor:
 x² - 15x + 50

• (x - 10)(x - 15)

• (x - 10)(x - 5)

• (x - 25)²

• (x - 5)²