Lateral and Surface Area of Prisms and Pyramids

Jesse needs to wrap the present shown below. How much wrapping paper would he need?

Which formula can be used to find the surface area of the present?

• SA=Ph+2B

• SA=2πrh+2πr²

• SA=Ph

• V=Bh

Tags

CCSS.7.G.B.6

What does "P" stand for in the surface area formulas?

• Perimeter

• Parallel

• Perimeter of the Base

• Pi

• 72 square cm

• 48 square cm

• 24 square cm

• 12 square cm

Tags

CCSS.7.G.B.6

Determine the total surface area of the figure.

• 96 cm²

• 84 cm²

• 144 cm²

Tags

CCSS.6.G.A.4

Find the total surface area of the rectangular prism.

• 77 cm2

• 17 cm2

• 7 cm2

• 70 cm2

Tags

CCSS.6.G.A.4

Find the total surface area of the figure formed by the net.

• 40 cm²

• 48 cm²

• 52 cm²

• 62 cm ²

Tags

CCSS.6.G.A.4

What is the total surface area of the triangular prism shown?

• 960 cm²

• 448 cm²

• 256 cm²

• 544 cm²

Tags

CCSS.7.G.B.6

A square pyramid is covered with decorative wrapping paper with no overlap.  The net of the box is shown on the right.  How many square centimeters of wrapping paper are needed to cover the surfaces of the box? 

• 108 cm²

• 324 cm²

• 180 cm²

• 432 cm²

Tags

CCSS.6.G.A.4

What is the total surface area of the rectangular pyramid whose net is shown?

• 400 in²

• 800 in²

• 1,200 in²

• 1,600 in²

Tags

CCSS.6.G.A.4

Find the total surface area of the following triangular pyramid. Each triangle is congruent, with a base of 7 ft. and a height of 6ft.

• 168 ft²

• 126 ft²

• 84 ft²

• 42 ft²

Tags

CCSS.7.G.B.6