Surface Area of Prisms and Pyramid Nets

Jesse needs to wrap the present shown below. How much wrapping paper would he need?

Which formula can be used to find the surface area of the present?

• SA=Ph+2B

• SA=2πrh+2πr²

• SA=Ph

• V=Bh

Tags

CCSS.7.G.B.6

Find the surface area of the triangular pyramid.

• 123.6 sq. feet

• 116.8 sq. feet

• 127.9 sq. feet

• 130.9 sq. feet

Tags

CCSS.7.G.B.6

Find the Surface Area

• 556 cm²

• 278 cm²

• 680 cm²

• 340 cm²

Tags

CCSS.7.G.B.6

Find the Surface Area

• 500 ft²

• 515 ft²

• 525 ft²

• 510 ft²

Tags

CCSS.7.G.B.6

What is the total surface area of the rectangular pyramid whose net is shown?

• 400 in²

• 800 in²

• 1,200 in²

• 1,600 in²

Tags

CCSS.7.G.B.6

A square pyramid is covered with decorative wrapping paper with no overlap.  The net of the box is shown on the right.  How many square centimeters of wrapping paper are needed to cover the surfaces of the box? 

• 108 cm²

• 324 cm²

• 180 cm²

• 432 cm²

Tags

CCSS.6.G.A.4

Find the total surface area of the prism.

• 48 square inches

• 64 square inches

• 88 square inches

• 76 square inches

Tags

CCSS.7.G.B.6

Find the surface area of this figure.

• 148 cm²

• 120 cm²

Tags

CCSS.7.G.B.6

What is the total surface area of the triangular prism shown?

• 486 in²

• 540 in²

• 576 in²

• 700 in²

Tags

CCSS.7.G.B.6

What is the surface area of this figure?

• 200 cm ²

• 800 cm ²

• 400 cm ²

• 100 cm ²

Tags

CCSS.7.G.B.6