Dividing Polynomials with Missing Terms

If you are missing a term in your polynomials (both dividend and divisor), you must put a zero as a coefficient place holder for that term.

• True

• False

• Only for the dividend

• Only for the divisor

Tags

CCSS.HSA.APR.D.6

What is the quotient when (10n² - 37n - 12) is divided by (n - 4)?

• (10n - 3)

• (3n - 10)

• (10n + 3)

• (3n + 10)

Tags

CCSS.HSA.APR.D.6

Is this division problem worked correctly?

• This is correct!

• This is incorrect!

Tags

CCSS.HSA.APR.D.6

Cam divided (x⁴ + 3x² - 4x - 2) by factor of (x-2) using synthetic division. His work is shown above. Which best describes his mistake?

• Cam wrote the remainder incorrectly.

• Cam did not use a zero place holder for the x³ term.

• Cam added instead of subtracting the rows.

• Cam should have used -2 as his division since the factor was x-2.

Tags

CCSS.HSA.APR.D.6

Find the quotient

Mathematical Equivalence

ON

Tags

CCSS.HSA.APR.D.6

Which term is missing in this problem?
2x³ + 5x² + 9 ÷
x + 3

• x⁴

• x³

• x²

• x

Tags

CCSS.HSA.APR.D.6

If you were dividing x⁶ + 4x³ + 2, how many 0's would you need when setting up the top row of your synthetic division?

• 0

• 2

• 4

• 6

Tags

CCSS.HSA.APR.D.6

2x³ - 5x² + 3x + 7 ÷ x - 2

• 2x³ - x² + x + 9

• 2x² - x + 1

• 2x² - x + 1 + 9/x-2

• 2x² - 9x - 15 - 23/x-2

Tags

CCSS.HSA.APR.D.6

3x³ + 5x - 1 ÷ x + 1

• 3x³ - 3x² + 8x - 9

• 3x² - 3x + 8 - 9/x+1

• 3x² + 3x + 8 + 7/x+1

• 3x³ + 3x² + 8x + 7

Tags

CCSS.HSA.APR.D.6

Find the remainder
(2x³ - 5x - 7) / (x + 2)

• -9

• 11

• -13

• -1

Tags

CCSS.HSA.APR.B.2