Systems of Linear Quadratic Solutions Algebraically

Solve the system of linear and quadratic equations using substitution:
y = 5
y = 2x² - 16x + 29

• (6, 5) and (2, 5)

• (2, 6)

• (6, 2)

• (5, 6) and (5, 2)

Determine the solution to the given linear-quadratic function.

• (0, 0)

• (3, 0)

• (2, -3)

• (-3, 2)

Determine the number of solutions to the given linear-quadratic system.

• 0 solutions

• 1 solution

• 2 solutions

• 3 solutions

• (-1,-5)

• (5,-5)

• (-1,-5) and (5,-5)

• (-5,5) 

Determine the number of solutions to the given linear-quadratic system.

• 0 solutions

• 1 solution

• 2 solutions

• 3 solutions

What are the solutions to the graphed system?

• (0,-2) and (-3,1)

• (-2,0) and (2,0)

• (0,-2) and (3,1)

• (2,2) and (1,0)

Which of the following represents the first step in solving:

y = x² + 3x - 5

y = x + 3

• x² - 3x + 5 = x - 3

• x² + 3x - 5 = x + 3

• x² + 3x - 5 + x + 3 = 0

• x² + 3x - 5 = 0

How many solutions does this system of equations have?

• one solution

• two solutions

• no solutions

• All of the above

Solve the depicted system algebraically. Change to y = form.

• (0,-7) and (1, 6)

• (0,-7) and (1, -6)

• (0, 7) and (1, -6)

• (-7,0) and (1, -6)

The system of a linear and a quadratic function can have the following number of solutions, EXCEPT

• No solution

• 1 solution

• 2 solutions

• more than 2 solutions