Polynomials Synthetic Division
Authored by Anthony Clark
Mathematics
12th Grade
CCSS covered
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20 questions
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1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
2x² + 2x - 4 R(-12)
2x² - 2x + 6 R(-23)
2x² - 2x + 8 R(-20)
2x² - 4x + 1 R0
Tags
CCSS.HSA.APR.D.6
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Use synthetic division
x - 7
x2 - 7
x + 7
x2 + 3x - 54
Tags
CCSS.HSA.APR.D.6
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Yes, (x-2) is a factor.
There is a remainder.
No, (x-2) is not a factor.
The remainder is zero.
Yes, (x-2) is a factor.
The remainder is zero.
No, (x-2) is not a factor.
There is a remainder.
Answer explanation
Two ways to solve:
Synthetic division using x = 2
OR
Remainder Theorem: (recommended) Evaluate for x=2 to find the remainder!
Tags
CCSS.HSA.APR.B.2
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What should be the correct order of the coefficients when setting up synthetic division for (3x-4x3+6x4+1)÷(x+3) ?
3 0 -4 6 1
6 -4 3 1 0
6 -4 0 3 1
-6 4 0 -3 -1
Tags
CCSS.HSA.APR.D.6
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Use synthetic division to divide the polynomial (2x^3 + 4x^2 - 3x + 1) by the binomial (x - 1).
2x^2 + 6x - 3
2x^2 + 4x + 3
2x^2 + 2x + 3
2x^2 + 6x + 3
Tags
CCSS.HSA.APR.D.6
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Divide using synthetic division
2x3 - 5x2 + 3x + 7 ÷ x - 2
2x3 - x2 + x + 9
2x2 - x + 1
2x2 - x + 1 + 9/(x - 2)
2x2 - 9x - 15 - 23/(x - 2)
Tags
CCSS.HSA.APR.D.6
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Divide using synthetic division
(2x³ + 4x² - 5) by (x + 3).
2x² + 2x - 4 R(-12)
2x² - 2x + 6 R(-23)
2x² - 2x + 8 R(-20)
2x² - 4x + 1 R0
Tags
CCSS.HSA.APR.D.6
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