Dividing Polynomials by Binomials Using Synthetic Division

Which of the following is a benefit of using synthetic division over long division?

• Synthetic division can be used for dividing by any polynomial of degree greater than 1.

• Synthetic division requires less writing and fewer calculations for polynomials divided by linear binomials.

• Synthetic division provides more detail about the quotient and remainder.

• Synthetic division is the only method that can be used to divide polynomials with complex roots.

When applying synthetic division to factor polynomials, what must be true about the divisor?

• The divisor must be a polynomial of degree 2 or higher.

• The divisor must be a linear polynomial with a leading coefficient of 1.

• The divisor can be any polynomial.

• The divisor must be a linear polynomial.

For synthetic division, what would be the number in the left hand box?

• 0

• 1

• 2

• 3

Use synthetic division to divide the polynomial (2x^3 + 4x^2 - 3x + 1) by the binomial (x - 1).

• 2x^2 + 6x - 3

• 2x^2 + 4x + 3

• 2x^2 + 2x + 3

• 2x^2 + 6x + 3

Divide using synthetic division (2x³ + 4x² - 5) by (x + 3).

• 2x² + 2x - 4 - 12/(x + 3)

• 2x² - 2x + 6 - 23/(x + 3)

• 2x² - 2x + 8 - 20/(x + 3)

• 2x² - 4x + 1

Use synthetic division to divide the polynomial (5x^3 + 2x^2 - 4x + 1) by the binomial (x + 3).

• 5x^2 - 13x + 35 - 104/(x - 3)

• 5x^2 - 13x + 35 + 104/(x + 3)

• 5x^2 - 13x + 35 - 104/(x + 2)

• 5x^2 - 13x + 35 - 104/(x + 3)

Use synthetic division to divide the polynomial (2x^4 - 5x^3 + 3x^2 + 4x - 1) by the binomial (x + 1).

• 2x^3 - 7x^2 + 10x - 1

• 2x^3 - 7x^2 + 10x + 6

• 2x^3 - 7x^2 + 10x + 1

• 2x^3 - 7x^2 + 10x - 6

Divide using synthetic division 
(2x³ + 4x² - 5) by (x + 3).

• 2x² + 2x - 4  R(-12)

• 2x² - 2x + 6  R(-23)

• 2x² - 2x + 8  R(-20)

• 2x² - 4x + 1  R0

Divide using synthetic division 2x³ - 5x² + 3x + 7 ÷ x - 2

• 2x³ - x² + x + 9

• 2x² - x + 1

• 2x² - x + 1 + 9/(x - 2)

• 2x² - 9x - 15 - 23/(x - 2)