Arithmetic and Geometric Sequences Practice

Arithmetic and Geometric Sequences Practice

9th Grade

20 Qs

quiz-placeholder

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Arithmetic and Geometric Sequences

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Arithmetic and Geometric Sequences Practice

Arithmetic and Geometric Sequences Practice

Assessment

Quiz

Mathematics

9th Grade

Hard

Created by

Anthony Clark

FREE Resource

20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The value of the first term is 10. The sequence has a common difference of 3. Which explicit equation correctly describes the sequence?

f(n) = 10 + 3(n - 1)

f(n) = 10 + 3n

f(n) = 3 + 10(n - 1)

f(n) = 3 + 10n

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The value of the first term is 4. The sequence has a common difference of 10. Which recursive equation correctly describes the sequence?

f(1) = 4 ; f(n) = f(n - 1) + 10

f(1) = 10 ; f(n) = f(n - 1) + 4

f(1) = 4 ; f(n - 1) = f(n) + 10

f(n) = 4 ; f(n) = f(n - 1) + 10

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The value of the first term is 12. The sequence has a common difference of 4. Which recursive equation correctly describes the sequence?

f(1) = 12 ; f(n) = f(n - 1) + 4

f(1) = 4 ; f(n) = f(n - 1) + 12

f(1) = 12 ; f(n - 1) = f(n) + 4

f(n) = 12 ; f(n) = f(n - 1) + 4

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The value of the 0th term is 2. The sequence has a common difference of 11. Which recursive equation correctly describes the sequence?

f(0) = 2 ; f(n) = f(n - 1) + 11

f(0) = 11 ; f(n) = f(n - 1) + 2

f(0) = 2 ; f(n - 1) = f(n) + 11

f(1) = 2 ; f(n) = f(n - 1) + 11

5.

DROPDOWN QUESTION

1 min • 1 pt

Arithmetic

Geometric

Answer explanation

Percentages are almost always Geometric.

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What is the sum of the first 20 terms of the arithmetic sequence 2, 5, 8, 11, ...?

590

610

630

650

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

The value of the first term is 6. The sequence has a common ratio of 3. Which recursive equation correctly describes the sequence?

f(0) = 6 ; f(n) = f(n - 1)  3

f(1) = 6 ; f(n) = f(n - 1) ⋅ 3

f(1) = 6 ; f(n) = f(n - 1) + 3

f(1) = 3 ; f(n - 1) = f(n) ⋅ 6

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