Polynomial Theorem

Quiz
•
Mathematics
•
11th Grade
•
Hard
Standards-aligned
Anthony Clark
FREE Resource
14 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the remainder of (3x3 -5x2 -4x +1) ÷ (x + 3)?
-25
25
113
-113
Tags
CCSS.HSA.APR.B.2
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
If 𝒙2+𝟑𝒙+𝟕 is divided by 𝒙+𝟐, then what is the remainder?
0
-3
9
5
Tags
CCSS.HSA.APR.B.2
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Use the remainder theorem to find the value of p(c):
p(x) = 2x2 - 3x + 1, c = 4.
p(4) = 45
p(4) = -43
p(4) = 21
p(4) = -19
Tags
CCSS.HSA.APR.B.2
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
3x2 - 2x + 1 = (x - 1)(3x2 + x + 2)
3x2 - 2x + 1 = (x - 1)(3x + 1) + 2
3x2 - 2x + 1 = (x - 1)(3x - 5) + 6
3x2 - 2x + 1 = (x - 1)(3x2 - 5x + 6)
Tags
CCSS.HSA.APR.D.6
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Use the remainder theorem to find the value of p(c): p(x) = 3x3 + 4x + 32, c = -2.
p(-2) = 0 so
3x3 + 4x + 32 =
(x + 2)(3x2 - 6x + 16)
p(-2) = 0 so
3x3 + 4x + 32 =
(x - 2)(3x2 - 6x + 16)
p(-2) = 36
p(-2) = 52
Tags
CCSS.HSA.APR.B.2
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Use the remainder theorem to find the value of p(c): p(x) = 4x3 + 3x + 38, c = -2.
p(-2) = 0 so
4x3 + 3x + 38 =
(x + 2)(4x3 - 8x + 19)
p(-2) = 0 so
4x3 + 3x + 38 =
(x - 2)(4x3 - 8x + 19)
p(-2) = 48
p(-2) = 60
Tags
CCSS.HSA.APR.B.2
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
You are given a polynomial and one of its zeros. Factor the polynomial and find all of the real zeros. x3 - 6x2 - x + 6, c = -1
x3 - 6x2 - x + 6 =
(x + 1)2 (x - 6); zeros are x = -1, 6
x3 - 6x2 - x + 6 =
(x - 1)2 (x - 6); zeros are x = 1, 6
x3 - 6x2 - x + 6 =
(x + 1)(x - 1)(x - 6); zeros are x = -1, 1,-6
x3 - 6x2 - x + 6 =
(x + 1)(x - 1)(x - 6); zeros are x = -1, 1, 6
Tags
CCSS.HSA.APR.B.2
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