
Solving System of Equations in Two Variables Using Elimination or Substitution
Authored by Anthony Clark
Mathematics
10th Grade
CCSS covered

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19 questions
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1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the solution to the system?
(0, 3)
(1, -1)
(-3, 1)
(1, 3)
Answer explanation
The lines intersect at (1,3) so that is the solution.
Tags
CCSS.8.EE.C.8B
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the first step in solving a system of equations by elimination?
Rewrite the equations so the variables are all on the same side and line up the like terms.
Get both equations in slope-intercept form.
Get both equations equal to zero.
Put the x terms first.
Answer explanation
We need all of the variables on the same side so that we can eventually add the left side of both equations together and add the right side of both equations together.
If the variables aren't on the same side of the equal-sign, then we can't combine like terms.
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
To eliminate a variable in the system, should you add the equations or subtract the equations?
Add
Subtract
Neither
Answer explanation
We want to add the equations together in order to eliminate one of the variables. We have opposite terms (3x and -3x) that will "cancel/zero out" (be eliminated) when we add the equations together.
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Which variable would be easiest to eliminate?
x
y
Neither
Answer explanation
The terms with x in them have opposite coefficients (4x and -4x), so they will be the easiest to eliminate when we add the equations together.
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
7. Solve the system of linear equations: 2x + 5y = 13 and 3x - 2y = 4
x = 4, y = 4
x = 3, y = 1
x = 2, y = 3
x = 5, y = 2
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
6.
DROPDOWN QUESTION
1 min • 1 pt
(a)
A
B
C
D
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Solve for x and y
3x + 2y = 16
7x + y = 19
(-2,5)
(-2,-5)
(2,-5)
(2,5)
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
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