Search Header Logo

Transformation of Functions

Authored by Anthony Clark

Mathematics

11th Grade

CCSS covered

Used 1+ times

Transformation of Functions
AI

AI Actions

Add similar questions

Adjust reading levels

Convert to real-world scenario

Translate activity

More...

    Content View

    Student View

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

The blue function is the original function f(x) = x3. Which of the following is the correct equation for the red function, g(x)?

g(x)=x3+1

g(x)=x3-1

g(x)=(x-1)3

g(x)=(x+1)3

Tags

CCSS.HSF.BF.B.3

2.

MULTIPLE CHOICE QUESTION

1 min • 12 pts

Media Image

If the blue graph is f(x) (the original function) and the red graph is the transformation, what is the equation of the red graph?

-f(x)

f(-x)

f-1(x)

f(2x)

3.

MULTIPLE CHOICE QUESTION

1 min • 12 pts

Media Image

If the blue function is f(x)=√x, the red function must be

g(x)=√(-x)

g(x)=√(x-1)

g(x)=√x-1

g(x)=-√x

Tags

CCSS.HSF.BF.B.3

4.

MULTIPLE CHOICE QUESTION

1 min • 12 pts

Media Image

If the blue function is f(x)=x2, then the red function must be

g(x)=x2-5

g(x)=x2+5

g(x)=(x-5)2

g(x)=(x+5)2

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image


If the blue is f(x)=x2, the red must be

g(x)=(x+3)2

g(x)=(x-3)2

g(x)=x2+3

g(x)=x2-2

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Describe the transformation from the parent graph

Reflect over x, right 3, down 4

Reflect over y, right 3, down 4

Reflect over x, right 3, up 4

Reflect over y, left 3, down 4

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Which equation describes the transformation of shifting f(x)=x2 two units right?

x2 + 2

x2 - 2

(x + 2)2

(x - 2)2

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Classlink

Continue with Classlink

Clever

Continue with Clever

or continue with

Microsoft

Microsoft

Apple

Apple

Others

Others

Already have an account?