Completing the Square When a Is Not 1

Convert to vertex form.

• y=-2(x+12)² - 67

• y=-2(x-12)² - 67

• y=-2(x-6)² - 67

• y=-2(x+6)² - 67

Convert to vertex form.

• y=3(x+1)² - 8

• y=3(x-1) ² - 8

• y=3(x+2)² - 8

• y=3(x-2)² - 8

Find the value of "c" that completes the square. Then rewrite the trinomial as a perfect square.

Tags

CCSS.HSA-REI.B.4B

Convert to vertex form.

• y=3(x+1)² - 8

• y=3(x-1) ² - 8

• y=3(x+2)² - 8

• y=3(x-2)² - 8

Which of the following will you have to do first when completing the square?

• take the square root of both sides

• Divide every term by a if a is not already 1

• Move the constant over to one side of the equation

Tags

CCSS.HSA-REI.B.4B

Solve by completing the square:
k² − 12k + 23 = 0

• {6 + √13, 6 - √13}

• {-6 + √13, -6 - √13}

• {6 + √59, 6 - √59}

• {-6 + √59, -6 - √59}

Tags

CCSS.HSA-REI.B.4B

• A
• B
• C
• D

Tags

CCSS.HSA-REI.B.4B

CCSS.HSN.CN.C.7

Complete the square but do not solve.

Tags

CCSS.HSA-REI.B.4B

What do you do to the b value to correctly complete the square?

• square it

• divide it by 2 and square the result

• divide it by 2 and take the square root of the result

• divide it by 2 only

Tags

CCSS.HSA-REI.B.4B

To solve by completing the square, what needs to be moved in this equation?
x² = 9 - 4x

• the -4x

• the 9

• the x²

Tags

CCSS.HSA-REI.B.4B