Factors of Polynomial Functions

Factor and find all zeros:
ƒ(x) = x³ + 5x² + 4x

• x = 0, 1, 4

• x = 0, 2, -2

• x = 0, -2, -2

• x = 0, -1, -4

Find all zeros:
ƒ(x) = x(2x + 1)(x - 2)

• x = 0, -½, 2

• x = 0, ½, 2

• x = 0, -½, -2

• x = 0, -2, 2

Solve by factoring:  2x³+ 7x² + 6x = 0

• x=0, x= 3/2 and x = 2

• x=0, x = -3/2 and x = -2

• x=0, x = 6 and x = 7

• x=2, x = -6 and x = -7

Find the zeros of the function and graph.
y=(x + 2)(x - 3)(3x - 5)

• x=-2, x=3, x=5/3

• x=2, x=-3, x=-3/5

• x=2, x=-3, x=5/3

• x=-2, x=3, x=5

State the zeros of the polynomial (include multiplicity):
f(x) = x(x+3)²(x - 2)

• x = 0, 3, 2

• x = 0, -3 (multiplicity of 2), 2

• -3, 2

• 0, 2 (multiplicity of 3)

What are the zeros of the polynomial and state their multiplicity at each.
y = (x - 5)(x + 2)²

• x = 5 multi 1,  x = 2 multi 2

• x = -5 multi 2, x = -2 multi 1

• x = 5 multi 1, x = -2 multi 2

• x = 5 multi 2, x = -2 multi 1

Solve by factoring: x² - 9x + 20 = 0

• x = -4 and x = -5

• x = 20 and x = -9

• x = 4 and x = 5

• x = -4 and x = 5

f(x)= x²(x – 2)³(x – 7)

State the zeros, include multiplicity.

• 0 (Mult of 2), 2 (Mult of 3), 7 (mult 1)

• 2 (Mult of 3), 7 (mult 1)

• 0, 2, 7

• 2 (mult of 2), 7 (mult of 3)

Write a polynomial function of least degree with integral coefficients that has the given zeros.

• A

• B

• C

• D

Select polynomial whose zeros and degree are given.
Zeros: – 5(multiplicity of 3), 9(multiplicity of 2), – 2, 4 Degree: 7

• (x + 5)³(x - 9)²(x + 2)(x - 4)

• (x + 5)³(x - 9)²(x + 2)⁷(x - 4)⁷

• (x + 5)³(x - 9)²(x + 2)

• (x + 5)(x - 9)(x + 2)(x - 4)