Factoring Review

What is the first step in solving 
(x + 2)(x - 3) = 0      ?

• Plug in zero for x

• Solve for x

• FOIL

• Set each binomial factor equal to zero

Solve for the values of x:
(x + 2)(x - 3) = 0

• { 2, 3 }

• { -2, -3 }

• { 2, 3 }

• { -2, 3 }

Solve by factoring:  2x²+ 7x + 6 = 0

• x= 3/2 and x = 2

• x = -3/2 and x = -2

• x = 6 and x = 7

• x = -6 and x = -7

Solve by factoring: 2x² - 5x - 12 = 0

• x = -4 and x = -6

• x = 4 and x = -3/2

• x = 4 and x = 6

• x = -4 and x = 3/2

Solve

a² + 2a - 24 = 0

• a = -6, 4

• a = 6, -4

• a = 12, -2

• a = 8, -3

Factor:

2n³ + 16n + 12

• 2n(n³ + 24n + 6)

• 2(n³ + 8n + 6)

• 2n(n³ + 8n + 6)

• 3(n³ + 8n + 6)

Factor:

10a⁴ + 16a + 10a²

• 2a(5a³ + 8 + 5a)

• 2a⁴(5a + 8a² + 5a³)

• 2a⁴(10 + 16a + 40a²)

• 3a³(5 + 8a + a²)

39y⁵ + 12y⁴ - 3y³

• 3y(13y⁴ + 4y³ - y²)

• 3y³(13y² + 4y - 1)

• y³(39y² + 12y - 3)

Factor:

80x⁵ - 70x² - 60x⁷

• 2x²(80x³ - 70 - 60x⁶)

• 10x²(80x⁴ - 70x - 60x⁶)

• 10x²(8x³ - 7 - 6x⁵)

• 3x²(80x³ - 40 - 60x⁵)

Factor completely

45xy + 15x³y + 10y

• 5y (9xy + 3x² + 2y)

• 5xy (9 + 3x² + 2)

• 5x (9y + 3xy + 2)

• 5y (9x + 3x³ + 2)