Factoring Algebra Review

Factor completely: 2x² - 20x

• x (2x - 10)

• 2 (x² - 10x)

• 2x (x - 10)

• Prime

Factor completely:
x² + 12x + 36

• (x + 6)²

• (x + 9)(x - 4)

• (x - 12)(x + 3)

• (x - 6)(x - 6)

Tags

CCSS.HSA.APR.C.4

Factor by grouping:

• (x² - 2)(x - 7)

• (x² + 2)(x - 7)

• (x² + 2)(x + 7)

• (x² - 2)(x + 7)

Solve the equation:

(x - 4)(x + 3) = 0

• x = 4, x = -3

• x = -4, x = 3

• x = 4

• x = 0

Tags

CCSS.HSA-REI.B.4B

• A

• B

• C

• D

• A

• B

• C

• D

Tags

CCSS.HSA.APR.B.2

• In Step 1 because the expression inside the parentheses needs to have a sum of -11x, not 11x.

• In Step 2 because the sign on x should be negative and the sign on 2 should be positive.

• In Step 3 because there is no need to multiply (x-2) by 1.

• In Step 4 because (x-2) should be written first.

What are the factors of this polynomial?

• (x - 2)(x + 1)

• (x - 2)(x - 1)

• (x + 2)(x + 1)

• (x + 2)(x - 1)

Tags

CCSS.HSA.APR.C.4

Factor 4b⁵+4b³+16b²

• 4b³(b⁴+b²+4b)

• 4b³(b⁴+4b+5)

• 4(b⁵+b³+4b²)

• 4b²(b³+b+4)

• A

• B

• C

• D

Tags

CCSS.HSA.APR.C.4