Polynomials Pretest

Solve the equation by factoring:

n²+11n +30 = 0

• x = -6, -5

• x = 6, 5

• x = 2, 15

• x = -2, -15

Tags

CCSS.HSA-REI.B.4B

Factor by grouping: (group the first 2, group the last 2. Take out the GCFs!) 5n³-10n²+3n-6

• (5n²+3)(n-2)

• (5n²-3)(n+2)

• (5n³+3)(n-2)

• 10n(n²-6)

Factor by grouping: (group the first 2, group the last 2. Take out the GCFs!) 4p³ + 8p² + 3p + 6

• (2p²+3)(p+2)

• (2p²+6)(p+4)

• (4p²+3)(p+2)

• (4p²+8p)(3p+6)

If the zeros of a polynomial are -1, 3, and 7 then what does the polynomial look like in factored form?

• (x-1)(x+3)(x+7)

• (x+1)(x-3)(x-7)

• -x² + 3x + 7

• (x-1)

Tags

CCSS.HSA.APR.B.3

What are the zeros in (x-5)(x+4)

• 4 and -5

• 5 and -4

• -4 and -5

• no zeros

Tags

CCSS.HSA.APR.B.2

• 13

• 20

• 101

• 7

Tags

CCSS.HSN.CN.C.9

Use the quadratic formula to find the solutions for

y = -x² - 5x + 12

• No Real Solution

• 
• 
• 

Tags

CCSS.HSA-REI.B.4B

Solve using the quadratic formula.
2x² - 9x - 35 = 0

• x = 7/2, x = -6

• x = -5/2, x =5

• x = -3/7, x =6

• x = -5/2, x = 7

Tags

CCSS.HSA-REI.B.4B

Add the polynomials:
(3x³+3x²–4x+5) + (x³–2x²+x–4)

• 4x³ + 1x² – 3x + 1

• 2x³ + 1x² - 5x + 9

• 6x³ + 1x - 1x² - 3

• 3x⁵ +1x - 1x⁵ - 3x

Tags

CCSS.HSA.APR.A.1

Multiply:
(4x+1)(5x−2)

• 20x² + 3x − 2

• 20x² − 11x + 5

• 20x² − 18x + 2

• 20x² − 3x − 2

Tags

CCSS.HSA.APR.A.1