Polynomial Functions and Solving Polynomial Equations

(2p²+3)(p+2)

(2p²+6)(p+4)

(4p²+3)(p+2)

(4p²+8p)(3p+6)

(x + 7)(x² - 7x + 49)

(x - 7)(x - 7)(x - 7)

(x - 7)(x² + 7x + 49)

(x + 7)(x + 7)(x + 7)

4, 1

-3, -1, 2, 5

-3, -1, 30, 2, 5

3, 1, -2, -5

2

3

4

6

y=(x-2)(x+5)(3x+2)

y=(x-2)(x+5)(2x+3)

y=(x+2)(x-5)(2x-3)

y=(x+2)(x-5)(3x-2)

$$f\left(x\right)=\left(x-1\right)^{2\ }\left(x+2\right)^{2\ }$$  

$$f\left(x\right)=\left(x+1\right)^2\left(x-2\right)^{2\ }$$  

$$f\left(x\right)=\left(x-1\right)\left(x+2\right)$$  

$$f\left(x\right)=\left(x+1\right)\left(x-2\right)$$  

$$f\left(x\right)=-\left(x+4\right)\left(x+1\right)^2\left(x-2\right)\left(x-4\right)$$  

$$f\left(x\right)=-\left(x-4\right)\left(x-1\right)^2\left(x+2\right)\left(x+4\right)$$  

$$f\left(x\right)=\left(x+4\right)\left(x+1\right)^{2\ }\left(x-2\right)\left(x-4\right)$$  

$$f\left(x\right)=\left(x-4\right)\left(x-1\right)^{2\ }\left(x=2\right)\left(x+4\right)$$  

$$y=\left(x+2\right)\left(x-1\right)^2$$  

$$y=\left(x-2\right)\left(x+4\right)\left(x+1\right)^2$$  

$$y=-\left(x+2\right)\left(x-1\right)^2$$  

$$y=-\left(x+1\right)^2\left(x-2\right)$$  

6

7

5

3