Conditional Probability Tree Diagram

Conditional Probability Tree Diagram

10th Grade

20 Qs

quiz-placeholder

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Conditional Probability Tree Diagram

Conditional Probability Tree Diagram

Assessment

Quiz

Mathematics

10th Grade

Practice Problem

Hard

Created by

Anthony Clark

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20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

P(B | A') = ?

0.7

0.4

0.12

1.15

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

P(A | B') = ?

0.2

0.3

2.75

1.75

Answer explanation

Media Image

When the given condition is the SECOND event on the tree diagram, you will need to do more math...

The denominator is the sum of BOTH outcomes that have the given condition.

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

the probability of an event based on the occurrence of another event

conditional

disjoint

complement

overlapping

uniform

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

What is the probability that a student plays a sport given they do not play an instrument? 

.2

.2222

.10

.5

Answer explanation

Media Image

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

When the given condition is the SECOND event on the tree diagram, for example P(A | B), you will need to do more math to find the denominator. Which image shows the highlighted branches that would be the denominator for P(A | B)?

Media Image
Media Image

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

What is the probability of a fast ball having been thrown, given the batter was a strike out? P(Fast | Strike) = ?

0.7

0.60

0.875

0.9

Answer explanation

Media Image

When the given condition is the SECOND event on the tree diagram, you will need to do more math...

The denominator is the sum of BOTH outcomes that have the given condition.

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

At Bob’s Burger Shop, you can order a burger with your choice of fries or salad and a soda or juice. The diagram below show the orders taken of one day.

Of the order with fries, what is the probability they would have a coke?

625/500 = 125%

75/500 = 15%

275/350 = 79%

625/350 = 179%

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