AP Stats Confidence Intervals for Means

AP Stats Confidence Intervals for Means

12th Grade

10 Qs

quiz-placeholder

Similar activities

Confidence Intervals for Normal and T-Distributions

Confidence Intervals for Normal and T-Distributions

12th Grade - University

14 Qs

Confidence Intervals Review

Confidence Intervals Review

11th Grade - University

10 Qs

Constructing a Confidence Interval for a Mean: STEP BY STEP

Constructing a Confidence Interval for a Mean: STEP BY STEP

12th Grade

15 Qs

Confidence Intervals and More

Confidence Intervals and More

University

11 Qs

AP Statistics Unit 6 - 7 Review

AP Statistics Unit 6 - 7 Review

11th - 12th Grade

14 Qs

Confidence Interval (t Distribution)

Confidence Interval (t Distribution)

University

10 Qs

AP Stats Nit

AP Stats Nit

11th - 12th Grade

10 Qs

AP Stats Inference Method

AP Stats Inference Method

12th Grade - University

15 Qs

AP Stats Confidence Intervals for Means

AP Stats Confidence Intervals for Means

Assessment

Quiz

Mathematics

12th Grade

Hard

Created by

Anthony Clark

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

A Census Bureau report on the income of Americans says that with 90% confidence the median income of all U.S. households in a recent year was $57,005 with a margin of error of $742. Which of the following is the most appropriate conclusion?

90% of all possible samples of this same size would result in a sample median that falls within $742 of $57,005.

90% of the households in the sample interviewed by the Census Bureau had incomes in the interval $57,005 ± $742.

90% of all households had incomes in the interval $57,005 ± $742.

The Census Bureau got the result $57,005 ± $742 using a method that will capture the true median income 90% of the time when used repeatedly.

We can be sure that the median income for all households in the country lies in the interval $57,005 ± $742.

Answer explanation

This interval does not tell us where the population median is for sure, nor does it tell us where individual incomes are. It only provides a set of plausible values for the population median.

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

You want to calculate a 98% confidence interval for a population mean with a sample of n = 20. What is the appropriate t*?

2.326

2.528

2.539

2.518

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Mrs. Soto wants to find the sample size needed to find with 95% confidence the mean amount of time her stats students spent on homework during the snow days. The population is approximately normal and the known standard deviation is 6 minutes. How large should the sample size be if she wants a margin of error of +- .5 minutes?

553

551

600

601

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

A researcher wants to find a confidence interval estimate of the mean time it takes to complete an order over the phone at a call center for a large retail company. He has selected a random sample of 18 orders and recorded the time to complete the order. The sample mean time was 4.27 minutes and the sample standard deviation was 0.78 minutes. Assuming the conditions needed for inference are met, which of the following is the appropriate 98% confidence interval?

4.27 ± 2.326 ⋅ (0.78/√18)

4.27 ± 2.054 ⋅ (0.78/√18)

4.27 ± 2.552 ⋅ (0.78/√18)

4.27 ± 2.567 ⋅ (0.78/√18)

4.27 ± 2.567 ⋅ (0.78/√17)

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Which of the following would not decrease the width of a confidence interval?

I only

II only

III only

I and II only

II and III only

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

An irate patient complained that the cost of a doctor's visit was too high.  She randomly surveyed 20 other patients and found that the mean amount of money they spent on each doctor's visit was $44.80.  The standard deviation of the sample was $3.53.  Find the 95% confidence interval of the population mean.

$43.15 - $46.45

$44.53 - $48.21

$42.65 - $48.25

$43.15 - $48.25

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

2000 children were surveyed and the report that followed said, "With 98% confidence, between 20% and 50% of all parents make their children eat breakfast." What does 98% confidence mean in this situation?

We can be 98% confident that the method used to get the intervals always gives the correct answer

98% of all parents will make their kids eat breakfast

When used repeatedly, the method used to find the interval produces intervals which include the true proportion about 98% of the time

The kids were 98% confident that they ate breakfast that day.

Create a free account and access millions of resources

Create resources
Host any resource
Get auto-graded reports
or continue with
Microsoft
Apple
Others
By signing up, you agree to our Terms of Service & Privacy Policy
Already have an account?