Solve Quadratics in Factored Form

What are the factors AND solutions of x² + 2x – 3 = 0

• (x - 2)(x + 1); x=2, x=-1

• (x + 1)(x - 3); x=-1, x=3

• (x + 2)(x - 1); x=-2, x=1

• (x - 1)(x + 3); x=1, x=-3

Tags

CCSS.HSA-REI.B.4B

Find the zeros of the equation: 
(x+10)(x-2) = 0

• 10 and 2

• -2 and 10

• -10 and 2

• -2 and -10

Tags

CCSS.HSA.APR.B.2

• -2, 4
• -8
• ±8
• No real solution

Tags

CCSS.HSA-REI.B.4B

• -2, 4
• -8
• ±8
• No real solution

Tags

CCSS.HSA-REI.B.4B

±1.5

1.5

±1

No real solution

• ±1.5

• 1.5

• ±1

• No real solution

Tags

CCSS.HSA-REI.B.4B

Suzie solves the equation below:
x² + 4x - 12 = 2
(x - 2)(x + 6) = 2, 
by setting x -2 = 0 and x + 6 = 0. 
Her solutions are x = 2 and x = -6.
Is Suzie correct? Why or why not?

• Yes, she factored correctly and then used the zero product property

• Yes, she factored correctly and then square rooted.

• No, she did factor correctly, but she can't use the zero product property as shown.

• No, she didn't factor correctly so the rest of her work is wrong. 

Tags

CCSS.HSA-REI.B.4B

Solve by factoring.
-4y² + 24y - 36 = 0

• -3

• 7/2

• 4

• 3

Tags

CCSS.HSA-REI.B.4B

Solve
a² + 2a - 24 = 0

• a = -6, 4

• a = 6, -4

• a = 12, -2

• a = 8, -3

Tags

CCSS.HSA-REI.B.4B

Convert x²-9x+20 to factored form and solve.

• (x-10)(x+2); x=-2, 10

• (x+4)(x+5); x=-5, -4

• (x-4)(x-5); x=4, 5

• Not factorable

Tags

CCSS.HSA-REI.B.4B

Find the expression equivalent to (x-1)(x-9)

• x²+9

• x²-10x+9

• x²-10x-9

• x²+10x+9

Tags

CCSS.HSA.APR.A.1