Modeling Exponential Growth and Decay Graphs

Quiz
•
Mathematics
•
9th Grade
•
Hard
+1
Standards-aligned
Anthony Clark
FREE Resource
10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Give the rate of growth:
y = 5(1.27)x
127%
27%
5
Tags
CCSS.HSF-IF.C.8B
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is a, the starting term, for the function: f(x) = 800(0.85)x?
800
0.85
0.15
x
Tags
CCSS.HSF.LE.B.5
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Rhonda deposited $3000 in an account in the Merrick National Bank, earning 4.2% interest, compounded annually. She made no deposits or withdrawals. Write an equation that can be used to find B, her account balance after t years.
B = 3000(1 – 4.2)t
B = 3000(1 + 4.2)t
B = 3000(1 – 0.042)t
B = 3000(1 + 0.042)t
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Marilyn collects old dolls. She purchases a doll for $450. Research shows this doll's value will increase by 2.5% each year. Write an equation that determines the value, V, of the doll t years after purchase.
V = 450(1 + 0.025)t
V = 450(1 – 0.025)t
V = 450(1 + 2.5)t
V = 450(1 – 2.5)t
Tags
CCSS.HSF.LE.A.2
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
A car was purchased for $25,000. Research shows that the car has an average yearly depreciation rate of 18.5%. Create a function that will determine the value, V(t), of the car t years after purchase.
V(t) = 25000(1 – 0.185)t
V(t) = 25000(1 + 0.185)t
V(t) = 25000(1 – 18.5)t
V(t) = 25000(1 + 18.5)t
Tags
CCSS.HSF.LE.A.2
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The bear population in a given area is currently 1580. They anticipate the bear population to decrease by 2% each year. Which function represents the population of bears, B, after t years.
B = 1580(0.02)
B = 1580(1 – 0.02)
B = 1580(1 + 0.02)
B = 1580(1 – 0.2)
Tags
CCSS.HSF.LE.A.2
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The population of a town is currently 6342 and is increasing by a rate of 1.3% each year. Which function represents the population of people, P, after t years.
P = 6342(1 + 1.3)t
P = 6342(1 – 1.3)t
P = 6342(1 + .013)t
P = 6342(1 – .013)t
Tags
CCSS.HSF.LE.A.2
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